问题
I have the following data.frame, called tableMS:
X Y Z T
1 375 855 455.7259 3777.856
2 395 969 347.8306 2506.7
3 449 811 309.9512 519.8513
4 451 774 278.291 717.8705
5 453 774 278.291 717.8705
6 455 774 278.291 717.8705
7 521 697 376.734 693.8541
8 529 855 455.7259 3777.856
9 531 855 455.7259 3777.856
10 609 774 278.291 717.8705
when I try to use the function melt()
MeltTable <- melt(tableMS,id=c("X","Y"))
I get the following error:
Error in match.names(clabs, names(xi)) :
names do not match previous names
I struggle to understand what happens, any idea?
Edit: I generated tableMS as portion of a bigger table and the output of str(tableMS) is:
'data.frame': 10 obs. of 4 variables:
$ X: num 375 395 449 451 453 455 521 529 531 609
$ Y: num 855 969 811 774 774 774 697 855 855 774
$ Z:List of 10
..$ : num 456
..$ : num 348
..$ : num 310
..$ : num 278
..$ : num 278
..$ : num 278
..$ : num 377
..$ : num 456
..$ : num 456
..$ : num 278
$ T:List of 10
..$ : num 3778
..$ : num 2507
..$ : num 520
..$ : num 718
..$ : num 718
..$ : num 718
..$ : num 694
..$ : num 3778
..$ : num 3778
..$ : num 718
回答1:
It works for me. I did the following.
library(reshape2)
tableMS <- read.table(text=' X Y Z T
1 375 855 455.7259 3777.856
2 395 969 347.8306 2506.7
3 449 811 309.9512 519.8513
4 451 774 278.291 717.8705
5 453 774 278.291 717.8705
6 455 774 278.291 717.8705
7 521 697 376.734 693.8541
8 529 855 455.7259 3777.856
9 531 855 455.7259 3777.856
10 609 774 278.291 717.8705',header=TRUE)
EDIT This still work even if you coerce Z
and T
to a list.
tableMS$Z <- as.list(tableMS$Z)
tableMS$T <- as.list(tableMS$T)
MeltTable <- melt(tableMS,id=c("X","Y"))
# MeltTable
# X Y variable value
# 1 375 855 Z 455.7259
# 2 395 969 Z 347.8306
# 3 449 811 Z 309.9512
# 4 451 774 Z 278.2910
# 5 453 774 Z 278.2910
# 6 455 774 Z 278.2910
# 7 521 697 Z 376.7340
# 8 529 855 Z 455.7259
# 9 531 855 Z 455.7259
# 10 609 774 Z 278.2910
# 11 375 855 T 3777.8560
# 12 395 969 T 2506.7000
# 13 449 811 T 519.8513
# 14 451 774 T 717.8705
# 15 453 774 T 717.8705
# 16 455 774 T 717.8705
# 17 521 697 T 693.8541
# 18 529 855 T 3777.8560
# 19 531 855 T 3777.8560
# 20 609 774 T 717.8705
edit don't work with reshape2 version 1.4.2
A workaround is to use data.table
package. BTW this solution is faster.
library(data.table)
tableMS$Z <- as.vector(as.list(tableMS$Z))
tableMS$T <- as.vector(as.list(tableMS$T))
setDT(tableMS)
melt(tableMS,id=c("X","Y"))
回答2:
I had this same problem, but the cause was different. I got the same error message "names do not match previous names", but it was due to using the package dplyr.
Turns out, it is a known issue with dplyr. According to the GitHub issue, it will occur on some version of dplyr and reshape but not on others.
The output from dplyr is not just a data.frame - it inherits from data.frame. So after using dplyr to produce data
this is the result:
class(data)
> [1] "tbl_df" "tbl" "data.frame"
melt(data, id = c("X", Y"))
>Error in match.names(clabs, names(xi)) :
names do not match previous names
To fix this issue, I had to convert the dplyr output to a data frame. This also appears to be the recommended way to combine these packages:
data <- as.data.frame(data)
class(data)
> [1] "data.frame"
melt(data, id = c("X", "Y"))
The last block then completes without error.
回答3:
try:
tableMS <- data.frame(tableMS)
Then melt tableMS the way you want.
来源:https://stackoverflow.com/questions/16941111/r-cannot-melt-data-frame