Schema for User Ratings - Key/Value DB

问题

We're using MongoDB and I'm figuring out a schema for storing Ratings.

Ratings will have values of 1-5.
I want to store other values such as fromUser

This is fine but the main question I have is setting it up so that recalculating the average is as efficient as possible.

SOLUTION 1 - Separate Ratings Class

The first thought was to create a separate Ratings class and store an array of pointers to Ratings in the User class. The reason I second guessed this is that we will have to query for all of the Ratings objects every time a new Rating comes in so that we can recalculate an average

...

SOLUTION 2 - Dictionary in User Class

The second thought was to store a dictionary in the User class directly that would store these Ratings objects. This would be slightly more lightweight than Solution 1, but we'd be re-writing the entire Ratings history of each user every time we update. This seems dangerous.

...

SOLUTION 3 - Separate Ratings Class with Separate Averages in User Class

Hybrid option where we have Ratings in their own class, and a pointer array to them, however, we keep two values in the User Class - ratingsAve and ratingsCount. This way when a new Rating is set we save that object but we can recalculate the ratingsAve easily.

SOLUTION 3 sounds best to me but I'm just wondering if we'd need to include periodic calibrations by requerying the Ratings history to reset the ratingsAve just to make sure everything checks out.

I might be overthinking this but I'm not that great at DB schema creation, and this seems like a standard schema issue that I should know how to implement.

Which is the best option to ensure consistency but also efficiency of recalculation?

回答1:

First of all 'Dictionary in User Class' is not a good idea. why? Adding extra rate object requires pushing a new item to the array, which implies the old item will be removed, and this insertion is so called "moving a document". Moving documents is slow and MongoDB is not so great at reusing empty space, so moving documents around a lot can result in large swaths of empty data file (some text in 'MongoDB The Definitive Guide' book).

Then what is the correct solution: assume you have a collection named Blogs, and want to implement a rating solution for your blog posts, and additionally keep track of every user-based rate operation.

The schema for a blog document would be like:

{
   _id : ....,
   title: ....,
   ....
   rateCount : 0,
   rateValue : 0,
   rateAverage: 0
}

You need another collection (Rates) with this document schema:

{
    _id: ....,
    userId: ....,
    postId:....,
    value: ..., //1 to 5
    date:....   
}

And you need to define a proper index for it:

db.Rates.ensureIndex({userId : 1, postId : 1})// very useful. it will result in a much faster search operation in case you want to check if a user has rated the post previously

When a user wants to rate, firstly you need to check whether the user has rated the post or not. assume the user is 'user1', the query then would be

var ratedBefore = db.Rates.find({userId : 'user1', postId : 'post1'}).count()

And based on ratedBefore, if !ratedBefore then insert new rate-document to Rates collection and update blog status, otherwise, user is not allowed to rate

if(!ratedBefore)
{
    var postId = 'post1'; // this id sould be passed before by client driver
    var userId = 'user1'; // this id sould be passed before by client driver
    var rateValue = 1; // to 5
    var rate = 
    {       
       userId: userId,
       postId: postId,
       value: rateValue,
       date:new Date()  
    };

    db.Rates.insert(rate);
    db.Blog.update({"_id" : postId}, {$inc : {'rateCount' : 1, 'rateValue' : rateValue}});
}

Then what is gonna happen to rateAverage? I strongly recommend to calculate it based on rateCount and rateValue on client side, it is easy to update rateAverage with mongoquery, but you shouldn't do it. why? The simple answer is: this is a very easy job for client to handle these kind of works and putting average on every blog document needs an unnecessary update operation.

the average query would be calculated as:

var blog = db.Blog.findOne({"_id" : "post1"});
var avg = blog.rateValue / blog.rateCount;
print(avg);

With this approach you will get maximum performance with mongodb an you have track of every rate based by user, post and date.

回答2:

I would do it a bit different: Have a User class and a Rating class and aggregate the number of ratings and rating average.

The Rating class

This is a bit of pseudo code, but the meaning should be obvious.

{
  _id:ObjectId(…),
  rating: Integer,
  rater: User._id
  rated: User._id
  date: ISODate()
}

In order to do the aggregation efficiently, you should at least create an index over rated:

db.ratings.ensureIndex({rated:1})

Now, you can decide between to approaches: either, you calculate the number of ratings and the average let's say once an hour and store it in an collection, let's say rate_averages, or you calculate those values on demand.

Precalculated

db.ratings.aggregate(
  // Aggregation
  [{
     $order: {
      _id: "$rated",
      ratings: { $sum:1 },
      average: { $avg: "$rating" }
    },
    {$out:'rate_averages'}
  ]
)

A document in the rate_averages collection will then look like this:

{
  _id:User._id,
  ratings: Integer,
  average: Float
}

and is easily queryable for the individual user's values, as _id is indexed automatically.

On demand

You'd use the same rating and almost the same aggregation query, except that we add a $match stage so we only work with the values for the user we want to know the stats for and leave out the $out stage and have the document to be returned directly:

db.ratings.aggregate([
  {
    $match:{ rated: <_id of the user we want the values for> },
  },
  {
    $order: {
      _id: "$rated",
      ratings: { $sum:1 },
      average: { $avg: "$rating" }
  }
])

which would return a single document as shown for the user in question.

With this approach and a proper data model, you can even do such things as "How many ratings were given by a specific user on a given date?" or "What are the most active raters/the most rated?" quite easily.

Please read the aggregation framework docs for further details. You might find the data modeling docs useful, too.

回答3:

The Below code can be used to get the average rating for each users.

db.ratings.aggregate([
 {
 $match:{ rated: '$user' },
 },
 {
 $order: {
  _id: "$rated",
  average: { $avg: "$rating" }
 }
 ])

来源：https://stackoverflow.com/questions/26914380/schema-for-user-ratings-key-value-db

标签

mongodb

database-schema