问题
Is there an easy way to replace an entire embedded document in an array? Say replacing:
{
"_id" : "2",
"name" : "name2",
"xyz..." : "xyz2..."
}
with:
{
"_id" : "2",
"name" : "name6",
"xyz..." : "xyz5..."
"morefields..." : "fields..."
}
Searching for _id (embedded). Or do I need to replace each field individually using $set?
{
"_id" : "2",
"users" : [{
"_id" : "1",
"name" : "name1",
"xyz..." : "xyz1..."
}, {
"_id" : "2",
"name" : "name2",
"xyz..." : "xyz2..."
}],
"name" : "main name"
}
回答1:
You are using the "array of objects" pattern. You can use the positional operator, it should look something like this:
coll.update( {'_id':'2', 'users._id':'2'}, {$set:{'users.$':{ "_id":2,"name":"name6",... }}}, false, true)
In my experience, the "array of objects" pattern is not optimal if the objects have a natural ID. In your case, this could be modeled as the following:
{
"_id" : "2",
"users" :
{ "1" : { "name" : "name1", "xyz..." : "xyz1..." },
"2" : { "name" : "name2", "xyz..." : "xyz2..." }
}
"name" : "main name"
}
In this case you can use the dot notation to easily update the item you want.
var newValue = { "name" : "name6", "xyz..." : "xyz5...", "morefields..." : "fields..." };
coll.update({_id: 2}, { $set: { "users.2" : newValue } });
来源:https://stackoverflow.com/questions/9200399/replacing-embedded-document-in-array-in-mongodb