问题
I have been trying for some time and believe I am fairly close to this, but I am fairly new to Unix so have been finding this difficult.
I have a folder, containing many folders, some of which have zip files in them, some which don't. I am trying to unzip all of the zip files in any sub directories in place.
For example I have:
files/A/something.java
files/B/somezipfile.zip
files/C/someotherfile.zip
files/D/AnotherZipFile.zip
I would like to unzip them (assuming the zips contain just .java files), to have a result like: files/A/something.java
files/B/javafile.java
files/C/someotherfilefromzip.java
files/D/Anotherfile.java
I don't mind if the ZIP files remain or are deleted after unzipping, either is fine.
What I have tried so far.
1) I expected I could use piping, which I am new to, like this:
find . -name *.zip | unzip
This doesn't work.
2) I spent some time searching, the closest I got using a solution online is:
find . -name '*.zip' -exec unzip '{}' ';'
This unzips, but unzips them into the current working directory, I wanted them to unzip in place. I also don't understand this command which I would like to as I am trying to learn.
Any help is much appreciated.
Thanks,
回答1:
find . -name '*.zip' -exec sh -c 'unzip -d `dirname {}` {}' ';'
This commands looks in current directory and in its subdirectories recursively for files with names matching *.zip
pattern. For file found it executes command sh
with two parameters:
-c
and
unzip -d `dirname <filename>` <filename>
Where <filename>
is name of file that was found. Command sh
is Unix shell interpreter. Option -c
tells shell that next argument should be interpreted as shell script. So shell interprets the following script:
unzip -d `dirname <filename>` <filename>
Before running unzip
shell expands the command, by doing various substitutions. In this particular example it substitutes
`dirname <filename>`
with output of command dirname <filename>
which actually outputs directory name where file is placed. So, if file name is ./a/b/c/d.zip
, shell will rub unzip
like this:
unzip -d ./a/b/c ./a/b/c/d.zip
In case you ZIP file names or directory names have spaces, use this:
find . -name '*.zip' -exec sh -c 'unzip -d "`dirname \"{}\"`" "{}"' ';'
回答2:
Use -execdir
instead of -exec
, which runs the command in the directory where the file is found, not the directory you run find
from.
find . -name '*.zip' -execdir unzip '{}' ';'
回答3:
find . -name '*.zip' | xargs -n1 unzip
来源:https://stackoverflow.com/questions/14813130/find-all-zips-and-unzip-in-place-unix