Going to a custom step with jQuery-steps

问题

I am using a jQuery-steps on my app to for a wizard-like situation. I am having trouble finding out how to change to a custom step though. Any help with this one?

$(function () {
    $("#wizard").steps({
        headerTag: "h2",
        bodyTag: "section",
        transitionEffect: "slideLeft",
        enableFinishButton: false,
        labels: {
            next: $('#next').html(),
            previous : $('#previous').html()

        },
        onStepChanged: function (event, currentIndex, priorIndex)
        {
            if( priorIndex == 0) {
                var selected = $('input[name=radio_wizard]:checked', '#radio_wizard').val()
                switch( selected ){
                    case 1:
                        // GOTO 1 
                        break;
                    case 2:
                        // GOTO 2 
                        break;
                    case 3:
                        // GOTO 3 
                        break;
                }
            }
      }
}

How to achieve this?

回答1:

I did this so I created this new function:

function _goToStep(wizard, options, state, index)
{
    return paginationClick(wizard, options, state, index);
}

And the call that is not implemented, put this:

$.fn.steps.setStep = function (step)
{

    var options = getOptions(this),
        state = getState(this);

    return _goToStep(this, options, state, step);

};

Just taking advantage of what already existed plugin.

Use:

wizard.steps("setStep", 1);

回答2:

I found a simple way to do this. you can use the jquery function

$("#wizard-t-2").get(0).click();

assuming you know what step you want to go to. this example would bring you to the third step of the wizard. use chromes editor to figure out what the exact id is of the step you want to go to.

回答3:

stepsWizard = $("#wizard").steps({
        forceMoveForward : true,
        enablePagination: false,
        titleTemplate : '<span class="number">#index#.</span> #title#'
    });

stepsWizard.steps("next"); // this will send us on next step :-)

回答4:

Check my following implementation, What do you think guys?

$.fn.steps.setStep = function (step)
{
  var currentIndex = $(this).steps('getCurrentIndex');
  for(var i = 0; i < Math.abs(step - currentIndex); i++){
    if(step > currentIndex) {
      $(this).steps('next');
    }
    else{
      $(this).steps('previous');
    }
  } 
};

And you can execute the new method very easy:

$("#form").steps("setStep", 4); //based on 0 (set the index)

Regards, Nicholls

回答5:

Based on the documentation, it seems to lack that functionality as of right now:

/*  
 * Sets a specific step object by index.  
 *  
 * @method setStep  
 * @param index {Integer} An integer that belongs to the position of a step  
 * @param step {Object} The step object to change  
 *
 */
$.fn.steps.setStep = function (index, step) 
{
    throw new Error("Not yet implemented!"); 
};

回答6:

Basing on @AbdulJamal answer, I've implemented it for any step:

$(function () {
    var stepsWizard = $("#wizard").steps({
        ...
    });

    // step variable handles current step (from 0)
    for(var i=0; i<step; i++) {
        stepsWizard.steps("next");
    }
});

Note that step variable must be defined and equal or greater than 0.

回答7:

function GotoSpecificStep(action, currentStep, number) {
    try
    {
        var stepsTogo = parseInt(currentStep) - parseInt(number);
        for (i = 1; i <= Math.abs(parseInt(stepsTogo)) ; i++) {
            if (action == "next") {
                $(".btnNext").click();
            }
            else if (action == "prev") {
                $(".btnPrevious").click();
            }
        }
    }
    catch(exception)
    {
        MsgBox(exception.message);
    }
}

回答8:

Adding to the answer above by @FernandoTholl, for clarification, wizard.steps("setStep", 1); goes in onStepChanged

$('#wizard').steps({
  onStepChanging: function (event, currentIndex, newIndex) {
      //blah, blah, blah, some code here
  },
  onStepChanged: function (event, currentIndex, newIndex) {
    $('#wizard').steps("setStep", 3);
  },
  onFinished: function () {
      ///more code
  }
});

回答9:

I did something like below to get it worked:

stepsWizard = $("#wizard").steps({
    headerTag: "h2",
    bodyTag: "section"
});

var indx = 3;
for (i = 0; i <= indx; i++) {
 stepsWizard.steps("next");
}

回答10:

Another simple solution:

var desiredStep = 0;
$("#steps-uid-0-t-" + desiredStep).click();

回答11:

Created this new function:

function _goToStep(wizard, options, state, index)
{
    return paginationClick(wizard, options, state, index);
}
And the call that is not implemented, put this:

Call that is not implemented, put this:

$.fn.steps.setStep = function (step)
{

    var options = getOptions(this),
        state = getState(this);

    return _goToStep(this, options, state, index); //Index Instead step

};

wizard.steps("setStep", 1);

works just fine

回答12:

onInit: function(event) {
        let div = event.currentTarget;
        let lis = div.getElementsByTagName('li');
        // Choose second tab
        // active is just show style, only effective after clicking tag a.
        lis[1].className += ' active';
        $(lis[1]).children('a').click();
    }

回答13:

I did this so I created this new function in jquery.steps.js, is important inserts before the $.fn.steps.setStep function:

function _goToStep(wizard, options, state, index)
{
    return paginationClick(wizard, options, state, index);
}

In jquery.steps.js find the $.fn.steps.setStep = function and replace then with:

$.fn.steps.setStep = function (step)
{

    var options = getOptions(this),
        state = getState(this);

    return _goToStep(this, options, state, step);

};

Use:

wizard.steps("setStep", 1);

来源：https://stackoverflow.com/questions/19957432/going-to-a-custom-step-with-jquery-steps