问题
I want to add link to ng-grid. Here is my code for your reference
<html ng-app="myApp">
<head lang="en">
<meta charset="utf-8">
<title>Getting Started With ngGrid Example</title>
<link href="../../Content/ng-grid.css" rel="stylesheet" type="text/css" />
<script src="../../Scripts/jquery-1.9.1.js" type="text/javascript"></script>
<script src="../../Scripts/jquery-ui-1.8.20.js" type="text/javascript"></script>
<script src="../../Scripts/angular.js" type="text/javascript"></script>
<script src="../../Scripts/ng-grid.js" type="text/javascript"></script>
<script src="../../Scripts/main.js" type="text/javascript"></script>
<script type="text/javascript">
var app = angular.module('myApp', ['ngGrid']);
app.controller('MyCtrl', function ($scope) {
$scope.myData = [{ name: "RK.PRABAKAR", age: 25, href: "<a href='#'>Link1</a>" },
{ name: "Yoga", age: 27, href: "<a href='#'>Link1</a>" },
{ name: "James", age: 27, href: "<a href='#'>Link1</a>" },
{ name: "Siva", age: 35, href: "<a href='#'>Link1</a>" },
{ name: "KK", age: 27, href: "<a href='#'>Link1</a>"}];
$scope.pagingOptions = {
pageSizes: [2, 4, 6],
pageSize: 2,
currentPage: 1
};
$scope.gridOptions = {
data: 'myData',
enablePaging: true,
showFooter: true,
enableCellSelection: true,
enableRowSelection: false,
enablePinning: true,
pagingOptions: $scope.pagingOptions,
enableCellEdit: true,
columnDefs: [{ field: 'name', displayName: 'Name', enableCellEdit: true },
{ field: 'age', displayName: 'Age', enableCellEdit: true },
{ field: 'href', displayName: 'Link', enableCellEdit: false }]
};
});
</script>
<style>
.gridStyle {
border: 1px solid rgb(212,212,212);
width: 500px;
height: 300px;
}
</style>
</head>
<body data-ng-controller="MyCtrl">
<div class="gridStyle" data-ng-grid="gridOptions"></div>
</body>
Right now data grid is working fine except href link in grid. Link is not rendered to html tag it is displayed as normal string. I want to add link to ng-grid from myData
回答1:
Update:
It has been noted that this answer does not work with ui-grid
. This is understandable since at the time of the answer only ng-grid
existed; however, substituting {{COL_FIELD}}
in place of {{row.getProperty(col.field)}}
allows the solution to be valid for both ng-grid
and ui-grid
.
I know I used COL_FIELD
in these situations around the time I wrote this answer, so I'm not sure of my rationale for answering with the longer row.getProperty(col.field)
…but in any event, use COL_FIELD
and you should be good to go with ng-grid
and ui-grid
.
Original (unchanged) Answer:
You just need to define a cell template for the Link field…
You can do this inline:
{
field: 'href',
displayName: 'Link',
enableCellEdit: false,
cellTemplate: '<div class="ngCellText" ng-class="col.colIndex()"><a href="{{row.getProperty(col.field)}}">Visible text</a></div>'
}
Or you can do this by using a variable (to keep your gridOptions a little cleaner:
var linkCellTemplate = '<div class="ngCellText" ng-class="col.colIndex()">' +
' <a href="{{row.getProperty(col.field)}}">Visible text</a>' +
'</div>';
{
field: 'href',
displayName: 'Link',
enableCellEdit: false,
cellTemplate: linkCellTemplate
}
Or you could even put your template in an external HTML file and point to the URL:
{
field: 'href',
displayName: 'Link',
enableCellEdit: false,
cellTemplate: 'linkCellTemplate.html'
}
…and you only need to store the URL as href
in myData
to work with this solution :)
Look here for an example of a cell template.
回答2:
The answer that Kabb5 gave is correct, but it appears that for newer versions of ui-grid, it does not work. Everything regarding the cellTemplate is valid, however, instead of
row.getProperty(col.field)
You need to do:
COL_FIELD
This was the only way I was able to get this to work.
回答3:
Right.
Levi's {{COL_FIELD}}
works with angular-ui-grid 3.0.0-rc.20
.
$scope.gridOptions.columnDefs = [
{ name: 'firstname' },
{ name: 'lastname'},
{ name: 'email', displayName: 'Email', allowCellFocus : false },
{
field: 'viewUrl',
displayName: 'View',
enableCellEdit: false,
cellTemplate: '<div class="ngCellText" ng-class="col.colIndex()"><a ng-href="{{COL_FIELD}}" class="glyphicon glyphicon-eye-open green"></a></div>'
},
{
field: 'editUrl',
displayName: 'Edit',
enableCellEdit: false,
cellTemplate: '<div class="ngCellText" ng-class="col.colIndex()"><a ng-href="{{COL_FIELD}}" class="glyphicon glyphicon-pencil blue"></a></div>'
},
{
field: 'id',
displayName: 'Delete',
enableCellEdit: false,
cellTemplate: '<div class="ngCellText" ng-class="col.colIndex()"><a ng-click="grid.appScope.deleteUser(COL_FIELD)" class="glyphicon glyphicon-remove red"></a></div>'
}
];
$scope.deleteUser = function(userId) {
alert('Delete '+userId);
};
回答4:
To get property of the object in a row, one can just use row.entity.propertyName
回答5:
This worked for me with ui-grid 4.0.7 and angular 1.6.6, my properties are easily accessible in row.entity:
cellTemplate: '<div class="ngCellText">
<a href="Users/{{row.entity.userId}}">{{row.entity.name}}</a>
</div>'
(added line breaks for clarity, remove when pasting)
来源:https://stackoverflow.com/questions/18310007/add-html-link-in-anyone-of-ng-grid