问题
I have an XML document that has a TextBlock that contains HTML code.
<TextBlock>
<h1>This is a header.</h1>
<p>This is a paragraph.</p>
</TextBlock>
In the actual XML, however, it is coded like this:
<TextBlock>
<h1>This is a header.</h1>
<p>This is a paragraph.</p>
</TextBlock>
So when I use <xsl:value-of select="TextBlock"/>
it displays all of the coding on the page. Is there a way using XSLT to convert <
to <
within the TextBlock element?
回答1:
<xsl:value-of select="TextBlock" disable-output-escaping="yes"/>
and the result:
<h1>This is a header.</h1>
<p>This is a paragraph.</p>
Firefox has a corresponding bug: https://bugzilla.mozilla.org/show_bug.cgi?id=98168, which contains a lot of comments and is an interesting reading.
I am looking for a fix now.
EDIT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:import href="disable-output-escaping.xsl"/>
<!-- https://bug98168.bugzilla.mozilla.org/attachment.cgi?id=434081 -->
<xsl:output method="xml" encoding="UTF-8" indent="yes"/>
<xsl:template match="/TextBlock">
<xsl:copy>
<xsl:call-template name="disable-output-escaping"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
When inspecting via Firebug, the result looks correct:
<textblock>
<h1>This is a header.</h1>
<p>This is a paragraph.</p>
</textblock>
来源:https://stackoverflow.com/questions/4492303/parsing-xml-string-using-xslt