hangs on open url with urllib (python3)

早过忘川 提交于 2019-12-18 08:09:12

问题


I try to open url with python3:

import urllib.request
fp = urllib.request.urlopen("http://lebed.com/")

mybytes = fp.read()    
mystr = mybytes.decode("utf8")
fp.close()

print(mystr)

But it hangs on second line. What's the reason of this problem and how to fix it?


回答1:


I suppose the reason is that the url does not support robot visiting a site visit. You need to fake a browser visit by sending browser headers along with your request

import urllib.request
url = "http://lebed.com/"
req = urllib.request.Request(
    url, 
    data=None, 
    headers={
        'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_9_3) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/35.0.1916.47 Safari/537.36'
    }
)
f = urllib.request.urlopen(req)

Tried this one on my system and it works.




回答2:


Agree with Arpit Solanki. Shown output for a failed request vs successful.

Failed
    GET / HTTP/1.1
    Accept-Encoding: identity
    Host: www.lebed.com
    Connection: close
    User-Agent: Python-urllib/3.5

Success
    GET / HTTP/1.1
    Accept-Encoding: identity
    Host: www.lebed.com
    Connection: close
    User-Agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_9_3) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/35.0.1916.47 Safari/537.36


来源:https://stackoverflow.com/questions/45768441/hangs-on-open-url-with-urllib-python3

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!