Tuple and function composition

问题

Is there a better way to express (\(a, b) -> a < b) with function composition? I feel like I'm missing something and experimenting with curry only confused me more.

回答1:

curry is the wrong thing to use here; it turns a function operating on tuples into a curried function. You want the opposite, which is uncurry:

uncurry :: (a -> b -> c) -> (a, b) -> c

In this case, it's uncurry (<).

(Another useful source for combinators useful in writing functions on tuples is Control.Arrow; since (->) is an instance of Arrow, you can read a b c as b -> c.)

回答2:

Looking at the types is the best way in Haskell to get the first idea, what any function does:

curry :: ((a, b) -> c) -> a -> b -> c
uncurry :: (a -> b -> c) -> (a, b) -> c

curry: function of pair → curried function (it curries a function).

uncurry: curried function → function of pair.

Haskell Wiki page on currying has small exercises at the end of the page:

Simplify curry id

Simplify uncurry const

Express snd using curry or uncurry and other basic Prelude functions and without lambdas

Write the function \(x,y) -> (y,x) without lambda and with only Prelude functions

Try to solve these exercises right now, they will give you a massive insight into Haskell type system and function application.

There are several interesting applications of uncurry, try to pass different arguments to functions below and see what they do:

uncurry (.) :: (b -> c, a -> b) -> a -> c
uncurry (flip .) :: (b -> a -> b1 -> c, b) -> b1 -> a -> c
uncurry (flip (.)) :: (a -> b, b -> c) -> a -> c
uncurry ($) :: (b -> c, b) -> c
uncurry (flip ($)) :: (a, a -> c) -> c

-- uncurry (,) is an identity function for pairs
uncurry (,) :: (a, b) -> (a, b)
uncurry (,) (1,2) -- returns (1,2)
uncurry uncurry :: (a -> b -> c, (a, b)) -> c
uncurry uncurry ((+), (2, 3)) -- returns 5

-- curry . uncurry and uncurry . curry are identity functions
curry . uncurry :: (a -> b -> c) -> (a -> b -> c)
(curry . uncurry) (+) 2 3 -- returns 5
uncurry . curry :: ((a, b) -> c) -> ((a, b) -> c)
(uncurry . curry) fst (2,3) -- returns 2

-- pair -> triple
uncurry (,,) :: (a, b) -> c -> (a, b, c)
uncurry (,,) (1,2) 3 -- returns (1,2,3)

来源：https://stackoverflow.com/questions/8993285/tuple-and-function-composition

标签

haskell

tuples

function-composition