问题
I am trying to have a plot pop up so the user can confirm that a fitting worked, but not hang up the entire process doing so. However, while the window appears, there is never anything in it, and it is "Not Responding". I suspect that there is a bad interaction with the subprocess functionality, as this code is front-ending and data processing for a simulation being run in C++.
import subprocess
import numpy as np
from matplotlib import pyplot as mpl
...
mpl.ion()
fig = mpl.figure()
ax = fig.add_subplot(1,1,1)
ax.grid(True)
ax.plot(x, y, 'g')
ax.scatter(X, Y, c='b')
ax.scatter(min_tilt, min_energy, c='r')
mpl.draw()
...
subprocess.call(prog)
The following subprocess does open. If I remove the ion()
call and use mpl.show()
, then the plot works fine, but the entire process holds up until the window is closed. I need the process to continue while the user looks at the graph. Is there a way to do this?
回答1:
Instead of the mpl.draw(), try:
mpl.pause(0.001)
when using the matplotlib interactive mode ion(). Note that this only works from matplotlib 1.1.1 RC or higher.
回答2:
This is probably overkill, but since no one had any better solutions I went to the threading module and it worked. If anyone has a simpler way to do this, please let me know.
import subprocess
import threading
from matplotlib import pyplot as mpl
...
class Graph(threading.Thread):
def __init__(self,X,Y,min_tilt, min_energy):
self.X = X
self.Y = Y
self.min_tilt = min_tilt
self.min_energy = min_energy
threading.Thread.__init__(self)
def run(self):
X = self.X
Y = self.Y
dx = (X.max()-X.min())/30.0
x = np.arange(X.min(),X.max()+dx,dx)
y = quad(x,fit)
fig = mpl.figure()
ax = fig.add_subplot(1,1,1)
ax.grid(True)
ax.plot(x, y, 'g')
ax.scatter(X, Y, c='b')
ax.scatter(self.min_tilt, self.min_energy, c='r')
mpl.show()
thread = Graph(X,Y,min_tilt,min_energy)
thread.start()
来源:https://stackoverflow.com/questions/11480167/matplotlib-ion-and-subprocesses