问题
I am trying to handle an event in BrowserField
when the user actually clicks a link.
I studied BrowserFieldListener
, tried its documentCreated()
method but that gives me a response when the page starts loading. I want a trigger the moment user clicks a link inside browserField.
What am i missing here?
回答1:
Override handleNavigationRequest() of ProtocolController like
ProtocolController controller = new ProtocolController(browserField) {
public void handleNavigationRequest(BrowserFieldRequest request) throws Exception {
/*
Here you get the redirection link using
request.getURL()
and do what you want to do
*/
// to display url in browserfield use
InputConnection inputConnection = handleResourceRequest(request);
browserField.displayContent(inputConnection, request.getURL());
}
};
browserField.getConfig().setProperty(BrowserFieldConfig.CONTROLLER, controller);
回答2:
Use the following class that was I used
public class CacheProtocolController extends ProtocolController{
public CacheProtocolController() {
super(browserField);
}
/**
* Handle navigation requests (e.g., link clicks)
*/
public void handleNavigationRequest(final BrowserFieldRequest request) throws Exception {
UiApplication.getUiApplication().invokeAndWait(new Runnable() {
public void run() {
// TODO Auto-generated method stub
Logger.debug("*******URL*******",request.getURL() );
});
}
/**
* Handle resource request (e.g., images, external css/javascript resources)
*/
public InputConnection handleResourceRequest(BrowserFieldRequest request) throws Exception {
return super.handleResourceRequest(request);
}
}
回答3:
I have solved this problem using the following class:
public class CacheProtocolController extends ProtocolController{
private SparseList sparseList = null;
private int imageIndex ;
private int click = 0;
private BrowserField browserField = null;
public CacheProtocolController(BrowserField browserField,SparseList sparseList,int imageIndex ) {
super(browserField);
this.sparseList = sparseList;
this.imageIndex = imageIndex;
}
/**
* Handle navigation requests (e.g., link clicks)
*/
public void handleNavigationRequest(final BrowserFieldRequest request) throws Exception {
UiApplication.getUiApplication().invokeAndWait(new Runnable() {
public void run() {
Logger.debug("*******URL*******",request.getURL() );
String requestUrl = null;
requestUrl = FileManipulations.replaceAll(request.getURL(), "file:///SDCard/BlackBerry/pictures/", "../");
Logger.debug("*******requestUrl*******",requestUrl );
Enumeration enumeration = sparseList.elements();
while (enumeration.hasMoreElements()) {
final News news = (News) enumeration.nextElement();
if(news.getDetailsURL().equalsIgnoreCase(requestUrl)){
if(click == 1){
click = 0;
UiApplication.getUiApplication().pushScreen(new DetailedNewsScreen(news.getImageURL() , imageIndex));
} else
click++;
}
}
}
});
}
/**
* Handle resource request (e.g., images, external css/javascript resources)
*/
public InputConnection handleResourceRequest(BrowserFieldRequest request) throws Exception {
return super.handleResourceRequest(request);
}
}
And in the MainScren
use the following
browserField = new BrowserField();
browserField.getConfig().setProperty(BrowserFieldConfig.CONTROLLER, new CacheProtocolController(browserField,List,index));
来源:https://stackoverflow.com/questions/11924182/blackberry-5-0-browserfield-handle-link-clicked