问题
In Java 6,
System.out.println(String.valueOf('\u0130').toLowerCase());
prints i (u0069
), but in Java 7 it prints i with double dots (u0069 u0307
).
I understand it is a Turkish character, but how do I make Java 7 print the same output as v6 using this code?
System.out.println(inputText.toLowerCase());
Also make sure that the code can handle international text without hardcoding the toLowerCase
function to use only Turkish locale.
回答1:
There is a quite detailed blog post about this i toLowerCase problem
Let me try to summarize the essential parts:
In Java 7 this method has indeed changed and handles this char differently than Java 6. The following code was added:
} else if (srcChar == '\u0130') { // LATIN CAPITAL LETTER I DOT
lowerChar = Character.ERROR;
}
==> This change results in the following way:
Basically the end result of this change is that for this specific case (the upper-case dotted I), Java 7 now consults a special Unicode character database (http://www.unicode.org/Public/UNIDATA/SpecialCasing.txt), which provides data on complex case-mappings. Looking at this file you can see several lines for the upper-case dotted I:
CODE LOWER TITLE UPPER LANGUAGE
0130; 0069 0307; 0130; 0130;
0130; 0069; 0130; 0130; tr;
0130; 0069; 0130; 0130; az;
来源:https://stackoverflow.com/questions/23524231/lower-case-of-turkish-character-dotted-i