问题
I have 2 dates, say 28-Mar-2011 and 29-Jun-2011. I need an sql query that will display the months between these 2 dates including the months containing the dates, ie. June, May, April and March.
回答1:
Something like this
SQL> ed
Wrote file afiedt.buf
select to_char( add_months( start_date, level-1 ), 'fmMonth' )
from (select date '2011-03-30' start_date,
date '2011-06-29' end_date
from dual)
connect by level <= months_between(
trunc(end_date,'MM'),
trunc(start_date,'MM') )
* + 1
SQL> /
TO_CHAR(ADD_MONTHS(START_DATE,LEVEL-
------------------------------------
March
April
May
June
should work.
回答2:
You can use the function MONTHS_BETWEEN
SELECT MOD( TRUNC( MONTHS_BETWEEN( '2011-07-29', '2011-03-28' ) ), 12 ) as MONTHS
FROM DUAL
Output
MONTHS
----------
4
回答3:
I needed an answer to this a couple of days ago. I found another solution I liked more:
select to_char(which_month, 'Mon-yyyy') month
from
(
select
add_months(to_date(:start_date,'mm-yyyy'), rownum-1) which_month
from
all_objects
where
rownum <= months_between(to_date(:end_date,'mm-yyyy'), add_months(to_date(:start_date,'mm-yyyy'), -1))
order by
which_month
)
You could of course use any format you want. I 'union'ed and summed over another set so that I'd get the months even when they didn't have results.
回答4:
Gonna add this solution just because I think it's much cleaner than the others:
SELECT ADD_MONTHS(TRUNC(TO_DATE('28-Mar-2011', 'DD-MON-YYYY'), 'MON'), ROWNUM - 1) date_out
FROM DUAL
CONNECT BY ADD_MONTHS(TRUNC(TO_DATE('28-Mar-2011', 'DD-MON-YYYY'), 'MON'), ROWNUM - 1)
<= TRUNC(TO_DATE('29-Jun-2011', 'DD-MON-YYYY'), 'MON')
回答5:
SELECT MIN (to_date((TO_CHAR (Actual_Date, 'DD-MM-RRRR')),'dd-mm-rrrr')) F_DATE,
MAX (to_date((TO_CHAR (Actual_Date, 'DD-MM-RRRR')),'dd-mm-rrrr')) T_DATE,
TO_CHAR (Actual_Date, 'MM-RRRR') TRX_MONTH
FROM ( SELECT TRUNC (TO_DATE (:P_FDATE, 'dd-mm-rrrr')) + LEVEL - 1
Actual_Date
FROM (SELECT TRUNC (TO_DATE (:P_FDATE, 'dd-mm-rrrr'), 'MM') - 1
AS dt
FROM DUAL)
CONNECT BY LEVEL <=
( TO_DATE (:P_TDATE, 'dd-mm-rrrr')
- TRUNC (TO_DATE (:P_FDATE, 'dd-mm-rrrr'))
+ 1))
GROUP BY TO_CHAR (Actual_Date, 'MM-RRRR')
ORDER BY 1
回答6:
declare
v_date_from_first_day date;
v_date_to_last_day date;
v_month_name varchar2(10);
v_month_number number;
v_year_number number;
v_month_diff number;
begin
v_date_to_last_day := to_date('31.12.2018');
v_date_from_first_day := to_date('01.01.2018');
select months_between(v_date_to_last_day,v_date_from_first_day) as diff into v_month_diff from dual;
for i in 1..round(v_month_diff, 2) loop
select
to_char(trunc(add_months(v_date_to_last_day - months_between(v_date_from_first_day, v_date_to_last_day), -i)), 'fmMonth') as month_nm,
to_char(trunc(add_months(v_date_to_last_day - months_between(v_date_from_first_day, v_date_to_last_day), -i)), 'MM') as month_num,
to_char(trunc(add_months(v_date_to_last_day - months_between(v_date_from_first_day, v_date_to_last_day), -i)), 'YYYY') as year_num
into v_month_name, v_month_number, v_year_number
from dual;
dbms_output.put_line(v_month_number || '/' || v_year_number);
dbms_output.put_line(v_month_name || '/' || v_year_number);
end loop;
end;
Output:
12/2018
11/2018
10/2018
9/2018
8/2018
7/2018
6/2018
5/2018
4/2018
3/2018
2/2018
1/2018
Here, month names are in Croatian
Prosinac/2018
Studeni/2018
Listopad/2018
Rujan/2018
Kolovoz/2018
Srpanj/2018
Lipanj/2018
Svibanj/2018
Travanj/2018
Ožujak/2018
Veljača/2018
Siječanj/2018
来源:https://stackoverflow.com/questions/6926923/how-to-get-a-list-of-months-between-2-given-dates-using-a-query