How to generate a frequency table in R with with cumulative frequency and relative frequency

醉酒当歌 提交于 2019-12-17 21:48:39

问题


I'm new with R. I need to generate a simple Frequency Table (as in books) with cumulative frequency and relative frequency.

So I want to generate from some simple data like

> x
[1] 17 17 17 17 17 17 17 17 16 16 16 16 16 18 18 18 10 12 17 17 17 17 17 17 17 17 16 16 16 16 16 18 18 18 10
[36] 12 15 19 20 22 20 19 19 19

a table like:

            frequency  cumulative   relative
(9.99,11.7]    2            2       0.04545455
(11.7,13.4]    2            4       0.04545455
(13.4,15.1]    1            5       0.02272727
(15.1,16.9]   10           15       0.22727273
(16.9,18.6]   22           37       0.50000000
(18.6,20.3]    6           43       0.13636364
(20.3,22]      1           44       0.02272727

I know it should be simple, but I don't know how.

I got some results using this code:

factorx <- factor(cut(x, breaks=nclass.Sturges(x)))
as.matrix(table(factorx))

回答1:


You're close! There are a few functions that will make this easy for you, namely cumsum() and prop.table(). Here's how I'd probably put this together. I make some random data, but the point is the same:

#Fake data
x <- sample(10:20, 44, TRUE)
#Your code
factorx <- factor(cut(x, breaks=nclass.Sturges(x)))
#Tabulate and turn into data.frame
xout <- as.data.frame(table(factorx))
#Add cumFreq and proportions
xout <- transform(xout, cumFreq = cumsum(Freq), relative = prop.table(Freq))
#-----
      factorx Freq cumFreq   relative
1 (9.99,11.4]   11      11 0.25000000
2 (11.4,12.9]    3      14 0.06818182
3 (12.9,14.3]   11      25 0.25000000
4 (14.3,15.7]    2      27 0.04545455
5 (15.7,17.1]    6      33 0.13636364
6 (17.1,18.6]    3      36 0.06818182
7   (18.6,20]    8      44 0.18181818



回答2:


The base functions table, cumsum and prop.table should get you there:

 cbind( Freq=table(x), Cumul=cumsum(table(x)), relative=prop.table(table(x)))
   Freq Cumul   relative
10    2     2 0.04545455
12    2     4 0.04545455
15    1     5 0.02272727
16   10    15 0.22727273
17   16    31 0.36363636
18    6    37 0.13636364
19    4    41 0.09090909
20    2    43 0.04545455
22    1    44 0.02272727

With cbind and naming of the columns to your liking this should be pretty easy for you in the future. The output from the table function is a matrix, so this result is also a matrix. If this were being done on something big it would be more efficient todo this:

tbl <- table(x)
cbind( Freq=tbl, Cumul=cumsum(tbl), relative=prop.table(tbl))



回答3:


If you are looking for something pre-packaged, consider the freq() function from the descr package.

library(descr)
x = c(sample(10:20, 44, TRUE))
freq(x, plot = FALSE)

Or to get cumulative percents, use the ordered() function

freq(ordered(x), plot = FALSE)

To add a "cumulative frequencies" column:

tab = as.data.frame(freq(ordered(x), plot = FALSE))
CumFreq = cumsum(tab[-dim(tab)[1],]$Frequency)
tab$CumFreq = c(CumFreq, NA)
tab

If your data has missing values, a valid percent column is added to the table.

x = c(sample(10:20, 44, TRUE), NA, NA)
freq(ordered(x), plot = FALSE)



回答4:


Yet another possibility:

 library(SciencesPo)
    x = c(sample(10:20, 50, TRUE))
    freq(x)



回答5:


My suggestion is to check the agricolae package... check it out:

library(agricolae)

weight<-c( 68, 53, 69.5, 55, 71, 63, 76.5, 65.5, 69, 75, 76, 57, 70.5,
+ 71.5, 56, 81.5, 69, 59, 67.5, 61, 68, 59.5, 56.5, 73,
+ 61, 72.5, 71.5, 59.5, 74.5, 63)

h1<- graph.freq(weight,col="yellow",frequency=1,las=2,xlab="h1")

print(summary(h1),row.names=FALSE)


来源:https://stackoverflow.com/questions/11148868/how-to-generate-a-frequency-table-in-r-with-with-cumulative-frequency-and-relati

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