问题
I have this string
ABCD1234, XYZ, ABCD1234, ABCD1234C, ABCD1234, abc, abcX, 1234U, 1234
and I want, but I don't want duplicates values
ABCD1234, XYZ, ABCD1234C, abc, abcX, 1234U, 1234,
I'm using below regex
select regexp_replace (
'ABCD1234, XYZ, ABCD1234, ABCD1234C, ABCD1234, abc, abcX, 1234U, 1234',
'([^,]+)(,\1)+', '\1'
) test
from dual;
回答1:
Try this, as per article http://www.dba-oracle.com/t_extract_comma_delimited_strings_oracle_sql.html:
select distinct str from
(select regexp_substr ('ABCD1234, XYZ, ABCD1234, ABCD1234C, ABCD1234, abc, abcX, 1234U, 1234', '[^, ]+',1, rownum) str
from dual
connect by level <= regexp_count ('ABCD1234, XYZ, ABCD1234, ABCD1234C, ABCD1234, abc, abcX, 1234U, 1234', '[^, ]+')) v;
Fiddle: http://sqlfiddle.com/#!4/c858d/5
回答2:
Here's one option:
SQL> with test (id, col) as
2 (select 1, 'ABCD1234, XYZ, ABCD1234, ABCD1234C, ABCD1234, abc, abcX, 1234U, 1234' from dual union
3 select 2, '111, 222, 111, ABCX2, FFE, 222' from dual
4 ),
5 t_rows as
6 (select id, regexp_substr(col, '[^, ]+', 1, column_value) col
7 from test,
8 table(cast(multiset(select level from dual
9 connect by level <= regexp_count(col, ',') + 1)
10 as sys.odcinumberlist))
11 ),
12 t_distinct as
13 (select distinct id, col
14 from t_rows
15 )
16 select id, listagg(col, ', ') within group (order by null) col
17 from t_distinct
18 group by id;
ID COL
---------- --------------------------------------------------
1 1234, 1234U, ABCD1234, ABCD1234C, XYZ, abc, abcX
2 111, 222, ABCX2, FFE
SQL>
来源：https://stackoverflow.com/questions/49009197/how-to-remove-duplicates-from-comma-separated-list-by-regex-in-oracle-but-i-don