问题
I'm designing an electrical engineering application. However, i'm stuck on this: I have the following array
<?php
// Static Array
$GroupOfEight = array (
array(0,1,3,2,4,5,7,6),
array(4,5,6,7,16,12,13,14),
array(12,13,15,14,8,9,11,10),
array(2,6,14,10,3,7,15,11),
array(1,3,5,7,13,15,9,11),
array(0,4,12,8,1,5,13,9),
array(0,1,3,2,8,9,11,10)
);
?>
And I have another array, but this one is one dimensional.
<?php
$myStack = array(0,1,3,2,4,5,7,6); //Dynamic, gets value by POST method.
?>
What I want to do is to check if $myStack is equal to any sub array of $GroupOfEight array. ( Number ordering is not important. The script should just check if every elements contained. It's not important if their order is same or not. )
Here is what I've done to solve the issue so far:
<?php
//Check if stackArray contains 8group
for($i=0; $i<count($GroupOfEight);$i++)
for($j=0; $j<count($GroupOfEight[$i]); $j++){
//$containsSearch = count(array_intersect($search_this,$all)) == count($search_this);
$containsSearch = count(array_intersect($stackArray,$GroupOfEight[$j])) == count($stackArray);
echo $containsSearch;
}
?>
Please help me correct my code or introduce me the solution of this issue, Thanks.
EDIT: It should give only 1 index number. for example stackArray is 0,1,3,2,4,1,2,3 and it should find GroupOfEight[N] that matches the same numbers, regardless of the order of the numbers. I should get the N if there is a matching case.
回答1:
Given your sample arrays, the output of this will be:
> 0
In case you HAD to have only one number output, this should do that:
<?php
//Check if stackArray contains 8group
$check=false;
for($i=0; $i<count($GroupOfEight);$i++){
//$containsSearch = count(array_intersect($search_this,$all)) == count($search_this);
$containsSearch = (count(array_intersect($stackArray,$GroupOfEight[$i])) == count($stackArray) && count(array_intersect($stackArray,$GroupOfEight[$i])) == count($GroupOfEight[$i]));
if($containsSearch && !$check){
echo $i; //This specifies which index in GroupOfEight contains a matching array
$check=true;
}
}
?>
EDIT: Made a function. Returns first matched index or -1 for no matches:
function searcheight($stackArray,$GroupOfEight){
for($i=0; $i<count($GroupOfEight);$i++){
$containsSearch = (count(array_intersect($stackArray,$GroupOfEight[$i])) == count($stackArray) && count(array_intersect($stackArray,$GroupOfEight[$i])) == count($GroupOfEight[$i]));
if($containsSearch){
return $i; //This specifies which index in GroupOfEight contains a matching array
}
}
return -1;
}
echo searcheight($stackArray,$GroupOfEight);
回答2:
You can try :
$searchKeys = array();
foreach ( $GroupOfEight as $key => $values ) {
(count(array_intersect($values, $myStack)) == count($myStack)) and $searchKeys[] = $key;
}
#Output all keys it found same match
var_dump($searchKeys);
#OR Output Each Array it found a match
foreach($searchKeys as $key)
{
var_dump($GroupOfEight[$key]);
}
回答3:
The thing that is wrong with your original approach is that you loop through GroupOfEight twice. You have two for-loops.
First you select every array within GroupOfEight and in the second for loop you go through each value of the array.
If you would like to use your original approach, get rid of the extra for loop:
echo "Hello, World!";
$GroupOfEight = array (
array(0,1,3,2,4,5,7,6),
array(4,5,6,7,16,12,13,14),
array(12,13,15,14,8,9,11,10),
array(2,6,14,10,3,7,15,11),
array(1,3,5,7,13,15,9,11),
array(0,4,12,8,1,5,13,9),
array(0,1,3,2,8,9,11,10)
);
$myStack = array(0,1,3,2,4,5,7,6); //Dynamic, gets value by POST method.
for($i=0; $i<count($GroupOfEight);$i++) {
$containsSearch = count(array_intersect($myStack,$GroupOfEight[$i])) == count($myStack);
if($containsSearch===true) {
echo "Woo! GroupOfEight[$i], <br/>" . print_r($GroupOfEight[$i], true) . "<br/>==<br/>" . print_r($myStack, true);
}
}
Demo: http://codepad.viper-7.com/0hRNHz
You could accomplish the same with array_diff:
for($i=0; $i<count($GroupOfEight);$i++) {
if(count(array_diff($myStack,$GroupOfEight[$i]))==0) {
echo "Woo! GroupOfEight[$i], <br/>" . print_r($GroupOfEight[$i], true) . "<br/>==<br/>" . print_r($myStack, true);
}
}
Demo: http://codepad.viper-7.com/6uLd9L
Update
A related SO post is: Check whether two array values are equal (ignoring order)
回答4:
You are comparing count which is not enough, as numbers could be changed. Try this:
// Static Array
$GroupOfEight = array (
array(0,1,3,2,4,5,7,6),
array(4,5,6,7,16,12,13,14),
array(12,13,15,14,8,9,11,10),
array(2,6,14,10,3,7,15,11),
array(1,3,5,7,13,15,9,11),
array(0,4,12,8,1,5,13,9),
array(0,1,3,2,8,9,11,10)
);
$myStack = array(0,1,3,2,4,5,7,6); //Dynamic, gets value by POST method.
$containsSearch = false;
foreach($GroupOfEight as $key => $value){
if ($myStack == $value) {
$containsSearch = true;
}
}
var_dump($containsSearch);
回答5:
Count the total of $GroupOfEight[$i]
Count the total of $myStack
if totals are equal:
In a loop -
if $myStack[$c] is in_array($GroupOfEight[$i]): $equal = 1
else $equal = 0; exit;
if $equal == 1 -> arrays are identical
回答6:
We do not need any loops. Try this
<?php
$GroupOfEight = array (
array(0,1,3,2,4,5,7,6),
array(4,5,6,7,16,12,13,14),
array(12,13,15,14,8,9,11,10),
array(2,6,14,10,3,7,15,11),
array(1,3,5,7,13,15,9,11),
array(0,4,12,8,1,5,13,9),
array(0,1,3,2,8,9,11,10)
);
$myStack = array(0,1,3,2,4,5,7,6);
$key = '';
$key = array_search($myStack,$GroupOfEight);
echo $key;
?>
Output
0
Note: Output $key is location of the array in $GroupOfEight i.e ( $GroupOfEight[0] )
来源：https://stackoverflow.com/questions/12867315/checking-if-an-array-contains-all-elements-of-another-array