问题
I need to export my nodes like this:
function recursive_simplify(node){
if(node.children){
for(var i =0;i<node.children.length;i++){
node.children[i] = recursive_simplify(node.children[i])
}
}
delete node['metadata'];
return node
}
$('body').on('click','.data-export', function () {
var tree=$.jstree._reference('#reference-data-exchange');
var checked = tree.get_checked();
var result = [];
for(var i=0, checkedLength = checked.length; i<checkedLength;i++)
{
var checkedJson = tree.get_json(checked[i],['id','rel','data-bin','data-pos'])[0];
checkedJson = recursive_simplify(checkedJson);
result.push(checkedJson);
}
alert(JSON.stringify(result));
});
it's works fine, BUT! I need all checked nodes(checked & undetermined) My code returns only checked. Plz help.
回答1:
get_all_checked: function(obj)
{
obj = !obj || obj === -1 ? this.get_container() : this._get_node(obj);
return obj.find(".jstree-checked, .jstree-undetermined");
};
use :
var checkedNodes = $(this).jstree("get_all_checked");
回答2:
Using 3.3.8 version of jsTree, to get all the undetermined nodes, get_undetermined
option is available.
Hence, you can use both get_selected
and get_undetermined
to fulfil your requirement.
For complete and working source code, you can refer https://everyething.com/Example-of-jsTree-to-get-all-checked-nodes
来源:https://stackoverflow.com/questions/11049874/how-to-get-all-checked-nodes-in-jstree