negative pow in python

问题

I have this problem

>>> import math
>>> math.pow(-1.07,1.3)  
Traceback (most recent call last):  
  File "<stdin>", line 1, in <module>  
ValueError: math domain error

any suggestion ?

回答1:

(-1.07)^1.3 will not be a real number, thus the Math domain error.

If you need a complex number, a^b must be rewritten into e^{b ln a}, e.g.

>>> import cmath
>>> cmath.exp(1.3 * cmath.log(-1.07))
(-0.6418264288034731-0.8833982926856789j)

If you just want to return NaN, catch that exception.

>>> import math
>>> def pow_with_nan(x, y):
...   try:
...     return math.pow(x, y)
...   except ValueError:
...     return float('nan')
...
>>> pow_with_nan(1.3, -1.07)   # 1.3 ** -1.07
0.755232399659047
>>> pow_with_nan(-1.07, 1.3)   # (-1.07) ** 1.3
nan

BTW, in Python usually the built-in a ** b is used for raising power, not math.pow(a, b).

>>> 1.3 ** -1.07
0.755232399659047
>>> (-1.07) ** 1.3
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: negative number cannot be raised to a fractional power
>>> (-1.07+0j) ** 1.3
(-0.6418264288034731-0.8833982926856789j)

回答2:

Don't use pow, and make the exponent complex (add 0j to it). Here is an example:

In [15]: (-1.07)**(1.3+0j)
Out[15]: (-0.64182642880347307-0.88339829268567893j)

No need for math functions :)

回答3:

I am using python 2.5.4 and I get this:

>>> import math
>>> math.pow(-1.07,1.3)  
nan

What python version are you using?

回答4:

Noninteger powers of complex (and negative) numbers involve an important subtlety. The exponential function is injective on the real line; i.e. exp(a) = exp(b) implies a = b. This is NOT so on the complex plane. Since exp(2*pi*i) = 1, the exponential function is 2*pi*i-periodic.

This leads to the problem: Which branch of the log function do we use? Said question is one of the central questions of complex analysis.

Python is responding intelligently to this situation. Unless you explicitly use its complex number constructor, you are going to be trafficking in reals. Since fractional powers of negatives are NEVER real, Python is appropriately throwing an exception.

回答5:

From the title of this post indicating that the power is negative, is it possible that you actually wanted 1.3^-1.07 rather than -1.07^1.3?

回答6:

Powers of negative bases are complex numbers. Here's an example that explains how to fix it:

from numpy import *
t  = arange(-3, 3, 0.1)

for n in range(0,len(t)):
    T = t[n]
    x = (complex(-0.5,0))**T
    print(T, x)

来源：https://stackoverflow.com/questions/4114740/negative-pow-in-python