问题
I'm trying to sort a linked list by finding the largest value, deleting it from its position, and then inserting it at the top of the list.
The difficulty I'm running into is the actual deleting and inserting at the top. The issue seems to be in the if condition in the while loop contained within the sortList function, but I'm not sure how to fix it.
Any help would be appreciated.
#include <stdio.h>
#include <stdlib.h>
typedef struct node{
int num;
struct node *next;
} Node, *NodePtr;
void printList(NodePtr np);
NodePtr makeList(void);
NodePtr makeNode(int n);
NodePtr sortList(NodePtr list);
int main(void) {
NodePtr list;
printf("Enter numbers for the list (0 to end)\n");
list = makeList();
printList(list);
list = sortList(list);
printList(list);
return 0;
}
NodePtr makeList(void) {
NodePtr makeNode(int), np, top, last;
int n;
top = NULL;
if(scanf("%d", &n) != 1)n = 0;
while(n != 0) {
np = makeNode(n);
if(top == NULL)top = np;
else last->next = np;
last = np;
if(scanf("%d", &n)!=1)n=0;
}
return top;
}
void printList(NodePtr np) {
while(np != NULL) {
printf("%d\n", np->num);
np = np->next;
}
}
NodePtr makeNode(int n) {
NodePtr np = (NodePtr)malloc(sizeof(Node));
np->num = n;
np->next = NULL;
return np;
}
NodePtr sortList(NodePtr list) {
NodePtr top = list;
NodePtr curr = NULL;
NodePtr largest;
NodePtr prev;
prev = NULL;
curr = top;
largest = top;
while(curr != NULL) {
prev = curr;
if(curr->num > largest->num) {
largest = curr;
prev->next = curr->next;
largest->next = top;
}
curr = curr->next;
}
if(prev == NULL) {
largest->next = top;
return largest;
}
return largest;
}
回答1:
There is issues in the sortList function.
This function only put some large nodes in the beginning of the list. It is not soting all the list. you can you a sort algorithm to sort the file : quicksort/ bubblesort/... i put a code doing a sort in the end of this answer.
here is a code doing the sort of the list :
//it is replacing largest node with first one then doing the same operation with sublist (list-first element)
NodePtr sortList(NodePtr list)
{
//
if(list == null || list->next == null)
return list; // the list is sorted.
//replace largest node with the first :
//1- find largest node :
NodePtr curr, largest,largestPrev;
curr = list;
largest = list;
prev = list;
largestPrev = list;
while(curr != NULL) {
if(curr->num > largest->num) {
largestPrev = prev;
largest = curr;
}
prev = curr;
curr = curr->next;
}
//largest node is in largest.
//2- switching firt node and largest node :
NodePtr tmp;
if(largest != list)
{
largestPrev->next = list;
tmp = list->next;
list->next = largest->next;
largest->next = tmp;
}
// now largest is the first node of the list.
// calling the function again with the sub list :
// list minus its first node :
largest->next = sortList(largest->next);
return largest;
}
回答2:
Here is my attempt to sort a singly linked list using QuickSort algorithm. If you know n then run time will be O(n log n). Check if this helps.
#include "malloc.h"
typedef struct node {
struct node *next;
int val;
} node;
bool insert_node(struct node **head, int val)
{
struct node *elem;
elem = (struct node *)malloc(sizeof(struct node));
if (!elem)
return false;
elem->val = val;
elem->next = *head;
*head = elem;
return true;
}
int get_lval(struct node *head, int l)
{
while(head && l) {
head = head->next;
l--;
}
if (head != NULL)
return head->val;
else
return -1;
}
void swap(struct node *head, int i, int j)
{
struct node *tmp = head;
int tmpival;
int tmpjval;
int ti = i;
while(tmp && i) {
i--;
tmp = tmp->next;
}
tmpival = tmp->val;
tmp = head;
while(tmp && j) {
j--;
tmp = tmp->next;
}
tmpjval = tmp->val;
tmp->val = tmpival;
tmp = head;
i = ti;
while(tmp && i) {
i--;
tmp = tmp->next;
}
tmp->val = tmpjval;
}
struct node *Quick_Sort_List(struct node *head, int l, int r)
{
int i, j;
int jval;
int pivot;
i = l + 1;
if (l + 1 < r) {
pivot = get_lval(head, l);
printf("Pivot = %d\n", pivot);
for (j = l + 1; j <= r; j++) {
jval = get_lval(head, j);
if (jval < pivot && jval != -1) {
swap(head, i, j);
i++;
}
}
swap(head, i - 1, l);
Quick_Sort_List(head, l, i);
Quick_Sort_List(head, i, r);
}
return head;
}
struct node *Sort_linkedlist(struct node *head)
{
struct node *tmp = head;
// Using Quick sort.
int n = 0;
while (tmp) {
n++;
tmp = tmp->next;
}
printf("n = %d\n", n);
head = Quick_Sort_List(head, 0, n);
return head;
}
void print_list(struct node *head)
{
while(head) {
printf("%d->", head->val);
head = head->next;
}
printf("\n");
}
int _tmain(int argc, _TCHAR* argv[])
{
struct node *head = NULL;
struct node *shead = NULL;
insert_node(&head, 10);
insert_node(&head, 12);
insert_node(&head, 9);
insert_node(&head, 11);
insert_node(&head, 7);
insert_node(&head, 1);
insert_node(&head, 3);
insert_node(&head, 8);
insert_node(&head, 5);
insert_node(&head, 2);
insert_node(&head, 4);
insert_node(&head, 6);
print_list(head);
shead = Sort_linkedlist(head);
print_list(shead);
return 0;
}
回答3:
This should really help you. It's a very nice post.
回答4:
By writing to largest->next you overwrote curr->next. So you end up restarting from the top all the time.
Make sure that:
- the list remains consistent
- your list iterator remains consistent
But overall, your code seems to be heavily broken, I believe there might be a couple other errors in your sorting logic.
回答5:
The following are some of the problems which exist in your sorting logic:
- You are setting the prev pointer to curr in the beginning of the loop itself which is incorrect. By doing this, you are making the current pointer and the previous node pointer as same which makes it impossible to delete the node.
- You should assign the largest pointer also to top whereby it facilitates the possibility of setting the largest->next to real top node.
The code can modified like below (Just a pointer, you need to check for other issues yourself):
while(curr != NULL)
{
if(curr->num > largest->num)
{
largest = curr;
prev->next = curr->next;
largest->next = top;
top = largest;
}
prev = curr;
curr = curr->next;
}
回答6:
// Program to sort a single linked list in ascending order
// (without exchanging data in the nodes)
/**************************************************************************
There are two methods of sorting presented here(At a time,we can use any of
these two functions to sort our single linked list.) -
1. Function 'void Sort()' - This function uses selection sort method(I
think).
In this function,a node whose data is the smallest in the list is made
as 'head' node(i.e. starting node of the list) by scanning the whole list
once.Then from the remaining list,again a node with the smallest data is
found out whose address is kept in the 'next' field of previous node(head
node).This process continues to sort the whole list.
2. Function 'void Sort_method2()' - This function uses insertion sort
method(I think).
In this function,starting from second node in the list, all previous node
data(starting from 'head' node) are compared with current reference node
(which is initially second node in the list).If 'data' field of current
reference node is smaller than that of any of its previous nodes,then
suitable changes in the 'next' field of corresponding nodes are made.If
data in the current reference node is smaller than that in the 'head' node,
then the current reference node is made as 'head' node.
*********************************************************************/
#include<stdio.h>
#include<conio.h>
#include<alloc.h>
#include<stdlib.h>
struct node
{
int data;
struct node *next;
};
struct node *head,*head1;
void Create_node(int data);
void display();
void Sort();
void Sort_method2();
void main()
{
int choice,d;
clrscr();
while(1)
{
printf("\n 1.Create new node");
printf("\n 2.Sort in ascending order");
printf("\n 3.Exit");
printf("\nEnter your choice : ");
scanf("%d",&choice);
switch(choice)
{
case 1: printf("\nEnter data :");
scanf("%d",&d);
Create_node(d);
break;
case 2: Sort(); // At a time,we can use any of these two
//Sort_method2(); // functions to sort our single linked list.
break;
case 3: exit(0);
default:exit(0);
}
} // end of while(1)
} // end of main()
//--------------------------------------------
void Create_node(int d)
{
struct node *newnode,*temp;
newnode = (struct node *)malloc(sizeof(struct node));
newnode -> data = d;
newnode -> next = NULL;
if(head == NULL)
head = newnode;
else
{
temp = head;
while(temp -> next != NULL)
temp = temp -> next;
temp -> next = newnode;
} // end of 'else'
} // end of 'Create_node(int d)'
//---------------------------------------------
void display() // Print linked list contents
{
struct node *temp;
printf("\nList contents are :\n");
temp = head;
while(temp != NULL)
{
printf(" Data = %d Address = %u\n",temp->data,temp);
temp = temp->next;
}
printf("\n");
}
//--------------------------------------------
void Sort()
{
struct node *t,*t1,*t2,*t3;
t1 = head;
head1 = head;
if(head == NULL)
printf("\nThe linked list is empty!");
else
{
while( (t2 = t1 -> next) != NULL)
{
while(t2 != NULL)
{
t3 = t2 -> next;
if( t1 -> data > t2 -> data)
{
t2 -> next = t1;
for(t = t1; t -> next != t2;t = t -> next);
t -> next = t3;
t1 = t2; // t1 = Node with smaller data
t2 = t3; // t2 = Node to be compared with t1
} // end of 'if'
else
{
// t1 = t1; // That is,no change in t1.
t2 = t3;
}
} // end of ' while(t2 != NULL)'
if(head == head1) // We want this action only for first pass of
{ // outer while() loop.Only initially, head = head1.
head = t1;
head1 = t1 -> next;
} // end of 'if(head == head1)'
else
{
for(t = head;t -> next != head1; t = t -> next);
t -> next = t1;
head1 = t1 -> next;
} // end of 'else'
t1 = t1 -> next;
} // end of 'while( (t2 = t1 -> next) != NULL)'
display(); // Display the list.
} // end of 'else' of 'if(head == NULL)'
} // end of 'Sort()'
//--------------------------------------------
void Sort_method2()
{
struct node *t,*t1,*t2,*tt;
if(head == NULL)
printf("\nThe linked list is empty!");
else
{
t1 = head -> next;
while(t1 != NULL) // This is i-loop(outer loop).
{
t2 = t1 -> next;
for(t = head; t != t1; t = t -> next) // This is j-loop(inner loop).
{
if(t1->data < t->data)
{
t1 -> next = t;
for(tt=head; tt->next != t1; tt=tt->next); //end of for loop in 'if'
tt -> next = t2;
if(t == head)
head = t1; // There is only one statement in this 'if'.
else // i.e.,'if(t != head)'
{
for(tt=head; tt->next != t; tt=tt->next);
tt -> next = t1;
}
break;
} // end of 'if'
} // end of outer 'for' loop
t1 = t2;
} // end of 'while'
display(); // Display the list.
} // end of 'else' of 'if(head == NULL)'
} // end of 'Sort_method2()'
来源：https://stackoverflow.com/questions/11813696/sorting-a-linked-list-in-c