问题
You can set image name when building a custom image, like this:
docker build -t dude/man:v2 . # Will be named dude/man:v2
Is there a way to define the name of the image in Dockerfile, so I don't have to mention it in the docker build
command?
回答1:
Tagging of the image isn't supported inside the Dockerfile. This needs to be done in your build command. As a workaround, you can do the build with a docker-compose.yml that identifies the target image name and then run a docker-compose build
. A sample docker-compose.yml would look like
version: '2'
services:
man:
build: .
image: dude/man:v2
That said, there's a push against doing the build with compose since that doesn't work with swarm mode deploys. So you're back to running the command as you've given in your question:
docker build -t dude/man:v2 .
Personally, I tend to build with a small shell script in my folder (build.sh) which passes any args and includes the name of the image there to save typing. And for production, the build is handled by a ci/cd server that has the image name inside the pipeline script.
回答2:
How to build an image with custom name without using yml file:
docker build -t image_name .
How to run a container with custom name:
docker run -d --name container_name image_name
回答3:
Here is another version if you have to reference a specific docker file:
version: "3"
services:
nginx:
container_name: nginx
build:
context: ../..
dockerfile: ./docker/nginx/Dockerfile
image: my_nginx:latest
Then you just run
docker-compose build
回答4:
You can do this using 'AS' FROM ubuntu:16.04 AS FooImage
来源:https://stackoverflow.com/questions/38986057/how-to-set-image-name-in-dockerfile