问题
I thought that if I used operators such as ">" and "<" in c++ to compare strings, these would compare them lexicographically, the problem is that this only works sometimes in my computer. For example
if("aa" > "bz") cout<<"Yes";
This will print nothing, and thats what I need, but If I type
if("aa" > "bzaa") cout<<"Yes";
This will print "Yes", why is this happening? Or is there some other way I should use to compare strings lexicographically?
回答1:
Comparing std::string
-s like that will work. However you are comparing string literals. To do the comparison you want either initialize a std::string with them or use strcmp:
if(std::string("aa") > std::string("bz")) cout<<"Yes";
This is the c++ style solution to that.
Or alternatively:
if(strcmp("aa", "bz") > 0) cout<<"Yes";
EDIT(thanks to Konrad Rudolph's comment): in fact in the first version only one of the operands should be converted explicitly so:
if(std::string("aa") > "bz") cout<<"Yes";
Will again work as expected.
回答2:
You are comparing "primitive" strings, which are of type char const *
.
The following is essentially equivalent to your example:
char const * s1 = "aa";
char const * s2 = "bz";
if ( s1 > s2 ) cout<<"Yes";
This is comparing the pointers (the memory addresses of the strings), not the contents.
@izomorphius has suggested some good solutions.
来源:https://stackoverflow.com/questions/14297185/comparing-strings-lexicographically