问题
I want to send files in JSON using http client I don't know how would I start can anyone suggest what should I need to do? I'm going to send data on this JSON format:
{
"Filename": "282850ad-de5c-498f-8280-2d4b6d77b774.jpg",
"ChunkId":1,
"ChunkLength":11397,
"FileLength":11397
}
As you see I'm going to send files in chunk. I don't know if I'm going to convert the file into byte array. If I needed can anyone give some sample code thanks.
回答1:
To send Text File or Image File on Server you can use MultiPartEntity.
DefaultHttpClient localDefaultHttpClient = new DefaultHttpClient();
FileBody localFileBody = new FileBody(new File(this.picturePath), "image/jpg");
HttpPost localHttpPost = new HttpPost("http://website.com/path/....");
MultipartEntity localMultipartEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
try
{
Log.d("picturepath", this.picturePath);
localMultipartEntity.addPart("Email", new StringBody("emailid@gmail.com"));
localMultipartEntity.addPart("password", new StringBody("password"));
localMultipartEntity.addPart("phone", new StringBody("9875......."));
localMultipartEntity.addPart("profilepicture", localFileBody);
localHttpPost.setEntity(localMultipartEntity);
HttpResponse localHttpResponse = localDefaultHttpClient.execute(localHttpPost);
System.out.println("responsecode" + localHttpResponse.getStatusLine().getStatusCode());
}
catch (Exception e)
{
Log.d("exception", e.toString());
}
This is working, as this code is part of my Running project.
回答2:
You can send Text file And media file using MultiPartEntity.
public String SendToServer(String aUrl,File Filename)
{
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(aUrl);
try
{
MultipartEntity entity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
entity.addPart("file", new FileBody(Filename));
entity.addPart("video-title", new StringBody("Video"));
entity.addPart("video-type", new StringBody("1"));
httpPost.setEntity(entity);
HttpContext context = new BasicHttpContext();
// Bind custom cookie store to the local context
context.setAttribute(ClientContext.COOKIE_STORE, Globals.sessionCookie);
HttpResponse response = httpClient.execute(httpPost, context);
HttpEntity resEntity = response.getEntity();
String Response = "";
if (response != null)
{
Response = EntityUtils.toString(resEntity);
}
return Response;
}
catch (IOException e)
{
e.printStackTrace();
}
return "Exception";
}
回答3:
Here is exactly what you want.
You can send JSON Object by GET or POST
HttpRequestWithEntity.java
import java.net.URI;
import java.net.URISyntaxException;
import org.apache.http.client.methods.HttpEntityEnclosingRequestBase;
public class HttpRequestWithEntity extends HttpEntityEnclosingRequestBase {
private String method;
public HttpRequestWithEntity(String url, String method) {
if (method == null || (method != null && method.isEmpty())) {
this.method = HttpMethod.GET;
} else {
this.method = method;
}
try {
setURI(new URI(url));
} catch (URISyntaxException e) {
e.printStackTrace();
}
}
@Override
public String getMethod() {
return this.method;
}
}
How to use???
I wrote method sendJSONObject for both POST & SET
/**
*
* @param url stands for API
* @param
* params[i][0] stands for column's name
* params[i][1] stands for value which respective with column's name
* @return InputStream which got from Server
*/
public static int sendJSONObject(IGetUserData iUserId, String method, String url, String[]... params) {
InputStream mInputStream = null;
HttpClient mHttpClient = null;
HttpRequestWithEntity mHttpGet = null;
int status = Def.REQUEST_INVALID;
try {
mHttpClient = new DefaultHttpClient();
mHttpGet = new HttpRequestWithEntity(url, method);
JSONObject mObject = new JSONObject();
for (String[] pair : params) {
mObject.put(pair[0], pair[1]);
}
StringEntity mStringEntity = new StringEntity(mObject.toString());
mStringEntity.setContentEncoding("UTF-8");
mStringEntity.setContentType("application/json");
mHttpGet.setEntity(mStringEntity);
HttpResponse mResponse = mHttpClient.execute(mHttpGet);
status = mResponse.getStatusLine().getStatusCode();
Log.d(TAG, "status: " + status);
if (mResponse != null &&
(status == Def.CREATED || status == Def.OK)) {
mInputStream = mResponse.getEntity().getContent();
if(mInputStream != null){
String json = StreamUtils.converStreamToString(mInputStream);
userId = JSONUtils.getUserId(json);
iUserId.sendUserId(userId);
Log.d("viet","userid = " + userId);
}
}
} catch (Exception e) {
Log.e(TAG, "Error during send");
status = Def.NETWORK_ERROR;
}
return status;
}
This way work correcty with me
And here if you want to upload photo or video and you can show progressbar if you want.
public static class UploadPhoto extends AsyncTask<String, Void, InputStream> {
private static final String TAG = "UploadImage";
byte[] buffer;
byte[] data;
//private long dataLength = 0;
private INotifyProgressBar iNotifyProgressBar;
private int user_id;
private IAddNewItemOnGridView mAddNewItemOnGridView;
public UploadPhoto(INotifyProgressBar iNotifyProgressBar,
IAddNewItemOnGridView mAddNewItemOnGridView, int user_id) {
this.iNotifyProgressBar = iNotifyProgressBar;
this.user_id = user_id;
this.mAddNewItemOnGridView = mAddNewItemOnGridView;
}
@Override
protected InputStream doInBackground(String... names) {
File mFile = null;
FileBody mBody = null;
File dcimDir = null;
try {
String fileName = names[0];
dcimDir = Environment
.getExternalStoragePublicDirectory(Environment.DIRECTORY_DCIM);
mFile = new File(dcimDir, Def.PHOTO_TEMP_DIR + fileName);
if (!mFile.isFile()) {
iNotifyProgressBar.notify(0, UploadStatus.FAILED);
return null;
}
HttpClient httpClient = new DefaultHttpClient();
HttpPost postRequest = new HttpPost(Def.BASE_URL
+ String.format("/%d/list", this.user_id));
final int maxBufferSize = 10 * 1024;
mBody = new FileBody(mFile, fileName, "image/jpeg", "UTF-8"){
int bytesRead, bytesAvailable, bufferSize;
InputStream mInputStream = super.getInputStream();
int dataLength = mInputStream.available();
@Override
public void writeTo(OutputStream out) throws IOException {
bytesAvailable = mInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
bytesRead = mInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
out.write(buffer, 0, bufferSize);
bytesAvailable = mInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = mInputStream.read(buffer, 0, bufferSize);
int progress = (int) (100 - ((bytesAvailable * 1.0) / dataLength) * 100);
Log.d(TAG, "Result: " + progress + "%");
if (progress == 100) {
iNotifyProgressBar.notify(progress, UploadStatus.SUCCESS);
} else {
iNotifyProgressBar.notify(progress, UploadStatus.UPLOADING);
}
}
}
@Override
protected void finalize() throws Throwable {
super.finalize();
if (mInputStream != null) {
mInputStream.close();
}
}
};
MultipartEntity reqEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
reqEntity.addPart("photo", mBody);
postRequest.setEntity(reqEntity);
HttpResponse response = httpClient.execute(postRequest);
InputStream mInputStream = response.getEntity().getContent();
return mInputStream == null ? null : mInputStream;
} catch (IOException e) {
Log.e(TAG, "Error causes during upload image: " + e.getMessage());
e.printStackTrace();
iNotifyProgressBar.notify(0, UploadStatus.FAILED);
} finally {
Log.v(TAG, "Close file");
if (mFile != null) {
mFile = null;
}
if (mBody != null) {
mBody = null;
}
if (dcimDir != null) {
dcimDir = null;
}
}
return null;
}
@Override
protected void onPostExecute(InputStream result) {
if (result == null) {
iNotifyProgressBar.notify(0, UploadStatus.FAILED);
} else {
PhotoInfo mPhotoInfo = ApiUtils.convertStreamToPhotoInfo(result);
if (mAddNewItemOnGridView != null && mPhotoInfo != null) {
mAddNewItemOnGridView.notifyAdded(mPhotoInfo);
Log.d(TAG, "Upload completed!!");
} else {
Log.d(TAG, "Upload is failed!!");
iNotifyProgressBar.notify(0, UploadStatus.FAILED);
}
}
}
@Override
protected void onPreExecute() {
super.onPreExecute();
}
}
来源：https://stackoverflow.com/questions/18050533/how-to-send-file-in-json-on-android