JavaScript - how to detect if the Custom URL scheme is available or not available?

佐手、 提交于 2019-12-17 16:08:11

问题


In Windows operating system i have a custom URI scheme, which is used from

IE, Firefox, Opera, Safari, Google Chrome

to launch Juniper router VPN SSH client (like Cisco). Basically it works as below if the SSH Client is installed, from the web page VPN SSH Client can be launched.

<a href="juniper:open"> VPN SSH Client </a>

Problem:

sometimes the user did not installed the Juniper router SSH client application from the CD/DVD box, therefore the juniper:open does nothing.

So in that case, i need to detect weather or not the URL scheme is available.

Therefore, I tried Javascript method but its not working exactly. because the juniper:open is actually not web link.

How do i then detect it please?

<script>
// Fails
function test1(){
  window.location = 'juniper:open';
  setTimeout(function(){
    if(confirm('Missing. Download it now?')){
      document.location = 'https://www.junper-affiliate.com/setup.zip';
    }
  }, 25);

  //document.location = 'juniper:open';
}

// Fails
function test2(h){
  document.location=h;
  var time = (new Date()).getTime();
  setTimeout(function(){
   var now = (new Date()).getTime();
   if((now-time)<400) {
    if(confirm('Missing. Download it now?')){
     document.location = 'https://www.junper-affiliate.com/setup.zip';
    } else {
     document.location=h;
    }
   }
  }, 300);
 }
</script>

Then:

<a onclick="test1()">TEST 1</a>
<a href="juniper:open" onclick="test2(this.href);return false;">TEST 2</a>

回答1:


EDIT Following suggestions in comments:

function goto(url, fallback) {
    var script = document.createElement('script'); 

    script.onload = function() { 
        document.location = url;
    } 
    script.onerror = function() { 
        document.location = fallback;
    } 
    script.setAttribute('src', url); 

    document.getElementsByTagName('head')[0].appendChild(script);

}

and

<a href="javascript:" onclick="goto('juniper:open', 'https://www.junper-affiliate.com/setup.zip');">TEST 2</a> 

The price you have to pay, is a duplicated request for the page.

EDIT

This is a good workaround for same-origin policy, which prevents an asynch version using XMLHTTPRequest to work properly, since SOP restricts cross-domain requests to http and juniper:open would therefore always fail.

function goto(url, fallback) {
    var xmlhttp=new XMLHttpRequest();
    xmlhttp.open('GET', url, false);
    try {
        xmlhttp.send(null);                  // Send the request now
    } catch (e) {
        document.location = fallback;
        return;
    }

    // Throw an error if the request was not 200 OK 
    if (xmlhttp.status === 200) {
        document.location = url;
    } else {
        document.location = fallback;
    }
}

EDIT

The initial solution below doesn't actually work 'cause no exception is being thrown if the protocal is not supported.

  try {
    document.location = 'juniper:open';
  } catch (e) {
    document.location = 'https://www.junper-affiliate.com/setup.zip';
  }



回答2:


After searching a lot i have not came to anything which can help to solve my problem. But this is what i am now making

1) Write a small tiny webserver which can run in the PC for 24/7 on boot, on crash. Use native python:

python -m SimpleHTTPServer [port]

2) tiny webserver will listen on port abnormal such as 10001 or such TCP ports which never get used

3) from Browser we have to communicate with the http://localhost:10001 just to get a reply

4) based on that reply we have to decide

Otherwise there is no way seems to be available

EDIT: Or you can do this way: InnoSetup - Is there any way to manually create cookie for Internet explorer?



来源:https://stackoverflow.com/questions/24571548/javascript-how-to-detect-if-the-custom-url-scheme-is-available-or-not-availabl

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