问题
This is my JSON Array :-
[
{
"firstName" : "abc",
"lastName" : "xyz"
},
{
"firstName" : "pqr",
"lastName" : "str"
}
]
I have this in my String object. Now I want to convert it into Java object and store it in List of java object. e.g. In Student object. I am using below code to convert it into List of Java object : -
ObjectMapper mapper = new ObjectMapper();
StudentList studentList = mapper.readValue(jsonString, StudentList.class);
My List class is:-
public class StudentList {
private List<Student> participantList = new ArrayList<Student>();
//getters and setters
}
My Student object is: -
class Student {
String firstName;
String lastName;
//getters and setters
}
Am I missing something here? I am getting below exception: -
Exception : com.fasterxml.jackson.databind.JsonMappingException: Can not deserialize instance of com.aa.Student out of START_ARRAY token
回答1:
You are asking Jackson to parse a StudentList
. Tell it to parse a List
(of students) instead. Since List
is generic you will typically use a TypeReference
List<Student> participantJsonList = mapper.readValue(jsonString, new TypeReference<List<Student>>(){});
回答2:
You can also use Gson for this scenario.
Gson gson = new Gson();
NameList nameList = gson.fromJson(data, NameList.class);
List<Name> list = nameList.getList();
Your NameList class could look like:
class NameList{
List<Name> list;
//getter and setter
}
回答3:
StudentList studentList = mapper.readValue(jsonString,StudentList.class);
Change this to this one
StudentList studentList = mapper.readValue(jsonString, new TypeReference<List<Student>>(){});
回答4:
I have resolved this one by creating the POJO class (Student.class) of the JSON and Main Class is used for read the values from the JSON in the problem.
**Main Class**
public static void main(String[] args) throws JsonParseException,
JsonMappingException, IOException {
String jsonStr = "[ \r\n" + " {\r\n" + " \"firstName\" : \"abc\",\r\n"
+ " \"lastName\" : \"xyz\"\r\n" + " }, \r\n" + " {\r\n"
+ " \"firstName\" : \"pqr\",\r\n" + " \"lastName\" : \"str\"\r\n" + " } \r\n" + "]";
ObjectMapper mapper = new ObjectMapper();
List<Student> details = mapper.readValue(jsonStr, new
TypeReference<List<Student>>() { });
for (Student itr : details) {
System.out.println("Value for getFirstName is: " +
itr.getFirstName());
System.out.println("Value for getLastName is: " +
itr.getLastName());
}
}
**RESULT:**
Value for getFirstName is: abc
Value for getLastName is: xyz
Value for getFirstName is: pqr
Value for getLastName is: str
**Student.class:**
public class Student {
private String lastName;
private String firstName;
public String getLastName() {
return lastName;
}
public String getFirstName() {
return firstName;
} }
回答5:
I made a method to do this below called jsonArrayToObjectList
. Its a handy static class that will take a filename and the file contains an array in JSON form.
List<Items> items = jsonArrayToObjectList(
"domain/ItemsArray.json", Item.class);
public static <T> List<T> jsonArrayToObjectList(String jsonFileName, Class<T> tClass) throws IOException {
ObjectMapper mapper = new ObjectMapper();
final File file = ResourceUtils.getFile("classpath:" + jsonFileName);
CollectionType listType = mapper.getTypeFactory()
.constructCollectionType(ArrayList.class, tClass);
List<T> ts = mapper.readValue(file, listType);
return ts;
}
回答6:
Try this. It works with me. Hope you too!
List<YOUR_OBJECT> testList = new ArrayList<>();
testList.add(test1);
Gson gson = new Gson();
String json = gson.toJson(testList);
Type type = new TypeToken<ArrayList<YOUR_OBJECT>>(){}.getType();
ArrayList<YOUR_OBJECT> array = gson.fromJson(json, type);
回答7:
You can use below class to read list of objects. It contains static method to read a list with some specific object type. It is included Jdk8Module changes which provide new time class supports too. It is a clean and generic class.
List<Student> students = JsonMapper.readList(jsonString, Student.class);
Generic JsonMapper class:
import com.fasterxml.jackson.databind.DeserializationFeature;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.datatype.jdk8.Jdk8Module;
import com.fasterxml.jackson.datatype.jsr310.JavaTimeModule;
import java.io.IOException;
import java.util.*;
import java.util.Collection;
public class JsonMapper {
public static <T> List<T> readList(String str, Class<T> type) {
return readList(str, ArrayList.class, type);
}
public static <T> List<T> readList(String str, Class<? extends Collection> type, Class<T> elementType) {
final ObjectMapper mapper = newMapper();
try {
return mapper.readValue(str, mapper.getTypeFactory().constructCollectionType(type, elementType));
} catch (IOException e) {
throw new RuntimeException(e);
}
}
private static ObjectMapper newMapper() {
final ObjectMapper mapper = new ObjectMapper();
mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
mapper.registerModule(new JavaTimeModule());
mapper.registerModule(new Jdk8Module());
return mapper;
}
}
来源:https://stackoverflow.com/questions/44589381/how-to-convert-json-string-into-list-of-java-object