How to convert JSON string into List of Java object?

别等时光非礼了梦想. 提交于 2019-12-17 16:03:28

问题


This is my JSON Array :-

[ 
    {
        "firstName" : "abc",
        "lastName" : "xyz"
    }, 
    {
        "firstName" : "pqr",
        "lastName" : "str"
    } 
]

I have this in my String object. Now I want to convert it into Java object and store it in List of java object. e.g. In Student object. I am using below code to convert it into List of Java object : -

ObjectMapper mapper = new ObjectMapper();
StudentList studentList = mapper.readValue(jsonString, StudentList.class);

My List class is:-

public class StudentList {

    private List<Student> participantList = new ArrayList<Student>();

    //getters and setters
}

My Student object is: -

class Student {

    String firstName;
    String lastName;

    //getters and setters
}

Am I missing something here? I am getting below exception: -

Exception : com.fasterxml.jackson.databind.JsonMappingException: Can not deserialize instance of com.aa.Student out of START_ARRAY token

回答1:


You are asking Jackson to parse a StudentList. Tell it to parse a List (of students) instead. Since List is generic you will typically use a TypeReference

List<Student> participantJsonList = mapper.readValue(jsonString, new TypeReference<List<Student>>(){});



回答2:


You can also use Gson for this scenario.

Gson gson = new Gson();
NameList nameList = gson.fromJson(data, NameList.class);

List<Name> list = nameList.getList();

Your NameList class could look like:

class NameList{
 List<Name> list;
 //getter and setter
}



回答3:


StudentList studentList = mapper.readValue(jsonString,StudentList.class);

Change this to this one

StudentList studentList = mapper.readValue(jsonString, new TypeReference<List<Student>>(){});



回答4:


I have resolved this one by creating the POJO class (Student.class) of the JSON and Main Class is used for read the values from the JSON in the problem.

   **Main Class**

    public static void main(String[] args) throws JsonParseException, 
       JsonMappingException, IOException {

    String jsonStr = "[ \r\n" + "    {\r\n" + "        \"firstName\" : \"abc\",\r\n"
            + "        \"lastName\" : \"xyz\"\r\n" + "    }, \r\n" + "    {\r\n"
            + "        \"firstName\" : \"pqr\",\r\n" + "        \"lastName\" : \"str\"\r\n" + "    } \r\n" + "]";

    ObjectMapper mapper = new ObjectMapper();

    List<Student> details = mapper.readValue(jsonStr, new 
      TypeReference<List<Student>>() {      });

    for (Student itr : details) {

        System.out.println("Value for getFirstName is: " + 
                  itr.getFirstName());
        System.out.println("Value for getLastName  is: " + 
                 itr.getLastName());
    }
}

**RESULT:**
         Value for getFirstName is: abc
         Value for getLastName  is: xyz
         Value for getFirstName is: pqr
         Value for getLastName  is: str


 **Student.class:**

public class Student {
private String lastName;

private String firstName;

public String getLastName() {
    return lastName;
}

public String getFirstName() {
    return firstName;
} }



回答5:


I made a method to do this below called jsonArrayToObjectList. Its a handy static class that will take a filename and the file contains an array in JSON form.

 List<Items> items = jsonArrayToObjectList(
            "domain/ItemsArray.json",  Item.class);

    public static <T> List<T> jsonArrayToObjectList(String jsonFileName, Class<T> tClass) throws IOException {
        ObjectMapper mapper = new ObjectMapper();
        final File file = ResourceUtils.getFile("classpath:" + jsonFileName);
        CollectionType listType = mapper.getTypeFactory()
            .constructCollectionType(ArrayList.class, tClass);
        List<T> ts = mapper.readValue(file, listType);
        return ts;
    }



回答6:


Try this. It works with me. Hope you too!

List<YOUR_OBJECT> testList = new ArrayList<>();
testList.add(test1);

Gson gson = new Gson();

String json = gson.toJson(testList);

Type type = new TypeToken<ArrayList<YOUR_OBJECT>>(){}.getType();

ArrayList<YOUR_OBJECT> array = gson.fromJson(json, type);



回答7:


You can use below class to read list of objects. It contains static method to read a list with some specific object type. It is included Jdk8Module changes which provide new time class supports too. It is a clean and generic class.

List<Student> students = JsonMapper.readList(jsonString, Student.class);

Generic JsonMapper class:

import com.fasterxml.jackson.databind.DeserializationFeature;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.datatype.jdk8.Jdk8Module;
import com.fasterxml.jackson.datatype.jsr310.JavaTimeModule;

import java.io.IOException;
import java.util.*;

import java.util.Collection;

public class JsonMapper {

    public static <T> List<T> readList(String str, Class<T> type) {
        return readList(str, ArrayList.class, type);
    }

    public static <T> List<T> readList(String str, Class<? extends Collection> type, Class<T> elementType) {
        final ObjectMapper mapper = newMapper();
        try {
            return mapper.readValue(str, mapper.getTypeFactory().constructCollectionType(type, elementType));
        } catch (IOException e) {
            throw new RuntimeException(e);
        }
    }

    private static ObjectMapper newMapper() {
        final ObjectMapper mapper = new ObjectMapper();
        mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
        mapper.registerModule(new JavaTimeModule());
        mapper.registerModule(new Jdk8Module());
        return mapper;
    }
}


来源:https://stackoverflow.com/questions/44589381/how-to-convert-json-string-into-list-of-java-object

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