问题
I have table which class is forum
. My jquery code:
<script type="text/javascript">
$(document).ready(function() {
$('.forum').bind("mouseover", function(){
var color = $(this).css("background-color");
$(this).css("background", "#380606");
$(this).bind("mouseout", function(){
$(this).css("background", color);
})
})
})
</script>
It perfectly works, but is it possible to do it in more efficient way without var color = $(this).css("background-color");
. Just after mouseout
leave the previous background-color and remove #380606
? Thank you.
回答1:
If you don't care about IE ≤6, you could use pure CSS ...
.forum:hover { background-color: #380606; }
.forum { color: white; }
.forum:hover { background-color: #380606 !important; }
/* we use !important here to override specificity. see http://stackoverflow.com/q/5805040/ */
#blue { background-color: blue; }
<meta charset=utf-8>
<p class="forum" style="background-color:red;">Red</p>
<p class="forum" style="background:green;">Green</p>
<p class="forum" id="blue">Blue</p>
With jQuery, usually it is better to create a specific class for this style:
.forum_hover { background-color: #380606; }
and then apply the class on mouseover, and remove it on mouseout.
$('.forum').hover(function(){$(this).toggleClass('forum_hover');});
$(document).ready(function(){
$('.forum').hover(function(){$(this).toggleClass('forum_hover');});
});
.forum_hover { background-color: #380606 !important; }
.forum { color: white; }
#blue { background-color: blue; }
<meta charset=utf-8>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p class="forum" style="background-color:red;">Red</p>
<p class="forum" style="background:green;">Green</p>
<p class="forum" id="blue">Blue</p>
If you must not modify the class, you could save the original background color in .data()
:
$('.forum').data('bgcolor', '#380606').hover(function(){
var $this = $(this);
var newBgc = $this.data('bgcolor');
$this.data('bgcolor', $this.css('background-color')).css('background-color', newBgc);
});
$(document).ready(function(){
$('.forum').data('bgcolor', '#380606').hover(function(){
var $this = $(this);
var newBgc = $this.data('bgcolor');
$this.data('bgcolor', $this.css('background-color')).css('background-color', newBgc);
});
});
.forum { color: white; }
#blue { background-color: blue; }
<meta charset=utf-8>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p class="forum" style="background-color:red;">Red</p>
<p class="forum" style="background:green;">Green</p>
<p class="forum" id="blue">Blue</p>
or
$('.forum').hover(
function(){
var $this = $(this);
$this.data('bgcolor', $this.css('background-color')).css('background-color', '#380606');
},
function(){
var $this = $(this);
$this.css('background-color', $this.data('bgcolor'));
}
);
$(document).ready(function(){
$('.forum').hover(
function(){
var $this = $(this);
$this.data('bgcolor', $this.css('background-color')).css('background-color', '#380606');
},
function(){
var $this = $(this);
$this.css('background-color', $this.data('bgcolor'));
}
);
});
.forum { color: white; }
#blue { background-color: blue; }
<meta charset=utf-8>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p class="forum" style="background-color:red;">Red</p>
<p class="forum" style="background:green;">Green</p>
<p class="forum" id="blue">Blue</p>
回答2:
Set the original background-color in you CSS file:
.forum{
background-color:#f0f;
}
You don't have to capture the original color in jQuery. Remember that jQuery will alter the style INLINE, so by setting the background-color to null you will get the same result.
$(function() {
$(".forum").hover(
function() {
$(this).css('background-color', '#ff0')
}, function() {
$(this).css('background-color', '')
});
});
回答3:
Try this , its working and simple
HTML
<html>
<head></head>
<body>
<div class="forum">
test
</div>
</body>
</html>
Javascript
$(document).ready(function() {
var colorOrig=$(".forum").css('background-color');
$(".forum").hover(
function() {
//mouse over
$(this).css('background', '#ff0')
}, function() {
//mouse out
$(this).css('background', colorOrig)
});
});
css
.forum{
background:#f0f;
}
live demo
http://jsfiddle.net/caBzg/
回答4:
This should be set directly in the CSS.
.forum {background-color: #123456}
.forum:hover {background-color: #380606}
If you are worried about the fact the IE6 will not accept hover over elements which are not links, you can use the hover event of jQuery for compatibility.
回答5:
HTML:
<div id="id">
</div>
<div id="hiddenDiv" style="display:none;"></div>
jQuery:
$('#id').hover(function(){
$("#hiddenDiv").css('display','block');
},
function(){
$("#hiddenDiv").css('display','none');
}
);
回答6:
After lot of struggle finally got it working. ( Perfectly tested)
The below example will also support the fact that color of already clicked button should not be changes
JQuery Code
var flag = 0; // Flag is to check if you are hovering on already clicked item
$("a").click(function() {
$('a').removeClass("YourColorClass");
$(this).addClass("YourColorClass");
flag=1;
});
$("a").mouseover(function() {
if ($(this).hasClass("YourColorClass")) {
flag=1;
}
else{
$(this).addClass("YourColorClass");
};
});
$("a").mouseout(function() {
if (flag == 0) {
$(this).removeClass("YourColorClass");
}
else{
flag = 0;
}
});
回答7:
This is my solution :
$(document).ready(function () {
$( "td" ).on({
"click": clicked,
"mouseover": hovered,
"mouseout": mouseout
});
var flag=0;
function hovered(){
$(this).css("background", "#380606");
}
function mouseout(){
if (flag == 0){
$(this).css("background", "#ffffff");
} else {
flag=0;
}
}
function clicked(){
$(this).css("background","#000000");
flag=1;
}
})
来源:https://stackoverflow.com/questions/3741157/change-background-color-on-mouseover-and-remove-it-after-mouseout