Test if an argument of a function is set or not in R

问题

I have a function f that takes two parameters (p1 and p2):

If for the parameter p2 no value was passed to the function, the value of p1^2 should be used instead. But how can I find out within the function, if a value is given or not. The problem is that the variable p2 is not initialized if there was no value. Thus I can't test for p2 being NULL.

f <- function(p1, p2) {
    if(is.null(p2)) {
        p2=p1^2
    }
    p1-p2
}

Is it somehow possible to check if a value for p2 was passed to the function or not? (I could not find an isset() - function or similar things.)

回答1:

You use the function missing() for that.

f <- function(p1, p2) {
    if(missing(p2)) {
        p2=p1^2
    }
    p1-p2
}

Alternatively, you can set the value of p2 to NULL by default. I sometimes prefer that solution, as it allows for passing arguments to nested functions.

f <- function(p1, p2=NULL) {
    if(is.null(p2)) {
        p2=p1^2
    }
    p1-p2
}

f.wrapper <-function(p1,p2=NULL){
    p1 <- 2*p1
    f(p1,p2)
}
> f.wrapper(1)
[1] -2
> f.wrapper(1,3)
[1] -1

EDIT: you could do this technically with missing() as well, but then you would have to include a missing() statement in f.wrapper as well.

回答2:

I think '?missing' should do it.

回答3:

In a case like this you can also use something like this:

f <- function(p1, p2 = p1 ^ 2) {
    p1-p2
}

See the part on Lazy evaluation at http://adv-r.had.co.nz/Functions.html

来源：https://stackoverflow.com/questions/7964830/test-if-an-argument-of-a-function-is-set-or-not-in-r