问题
<?php
$URL="http://cor-forum.de/forum/images/smilies/zombie.png";
list($width, $height) = getimagesize($URL);
echo 'width: '.$width.'<br>
height: '.$height;
?>
This results in the following output:
width:
height:
EDIT and I get the following warning:
Warning: getimagesize(http://cor-forum.de/forum/images/smilies/zombie.png): failed to open stream: HTTP request failed! HTTP/1.1 403 Forbidden in /home/webpages/lima-city/regnum-forum/html/DATEIEN/scheisstest.php on line 6
--whereas it displays the right values if I use another picture like
$URL='http://getfavicon.appspot.com/http://google.com?defaulticon=1pxgif';
EDIT: I'd like to enable the inclusion of external images in a forum, but I want to check their size first. So, what can I do to get the size of an image, whose server is "blocking me"?
EDIT: allow_url_fopen is set to ON, yes.
回答1:
Faking the HTTP referer field seems to work on this one:
<?php
function getimgsize($url, $referer = '')
{
$headers = array(
'Range: bytes=0-32768'
);
/* Hint: you could extract the referer from the url */
if (!empty($referer)) array_push($headers, 'Referer: '.$referer);
$curl = curl_init($url);
curl_setopt($curl, CURLOPT_HTTPHEADER, $headers);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
$data = curl_exec($curl);
curl_close($curl);
$image = imagecreatefromstring($data);
$return = array(imagesx($image), imagesy($image));
imagedestroy($image);
return $return;
}
list($width, $heigth) = getimgsize('http://cor-forum.de/forum/images/smilies/zombie.png', 'http://cor-forum.de/forum/');
echo $width.' x '.$heigth;
?>
Source of code
回答2:
Looks like your having problem with mentioned URL can you try the below code I have not done anything just changed the URL,
URL = "http://forums.phpfreaks.com/uploads/profile/photo-thumb-68615.jpg";
list($width, $height) = getimagesize($URL);
echo 'width: ' . $width . '<br>height: ' . $height;
回答3:
set PHP memory limit to maximum 256 Mb to fix it
来源:https://stackoverflow.com/questions/25230949/php-getimagesize-not-working