forward declaration of a struct in C?

问题

#include <stdio.h>

struct context;

struct funcptrs{
  void (*func0)(context *ctx);
  void (*func1)(void);
};

struct context{
    funcptrs fps;
}; 

void func1 (void) { printf( "1\n" ); }
void func0 (context *ctx) { printf( "0\n" ); }

void getContext(context *con){
    con=?; // please fill this with a dummy example so that I can get this working. Thanks.
}

int main(int argc, char *argv[]){
 funcptrs funcs = { func0, func1 };
   context *c;
   getContext(c);
   c->fps.func0(c);
   getchar();
   return 0;
}

I am missing something here. Please help me fix this. Thanks.

回答1:

Try this

#include <stdio.h>

struct context;

struct funcptrs{
  void (*func0)(struct context *ctx);
  void (*func1)(void);
};

struct context{
    struct funcptrs fps;
}; 

void func1 (void) { printf( "1\n" ); }
void func0 (struct context *ctx) { printf( "0\n" ); }

void getContext(struct context *con){
    con->fps.func0 = func0;  
    con->fps.func1 = func1;  
}

int main(int argc, char *argv[]){
 struct context c;
   c.fps.func0 = func0;
   c.fps.func1 = func1;
   getContext(&c);
   c.fps.func0(&c);
   getchar();
   return 0;
}

回答2:

A struct (without a typedef) often needs to (or should) be with the keyword struct when used.

struct A;                      // forward declaration
void function( struct A *a );  // using the 'incomplete' type only as pointer

If you typedef your struct you can leave out the struct keyword.

typedef struct A A;          // forward declaration *and* typedef
void function( A *a );

Note that it is legal to reuse the struct name

Try changing the forward declaration to this in your code:

typedef struct context context;

It might be more readable to do add a suffix to indicate struct name and type name:

typedef struct context_s context_t;

来源：https://stackoverflow.com/questions/9999512/forward-declaration-of-a-struct-in-c

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struct

declaration

forward