问题
I am making HTTP requests using the requests library in python, but I need the ip address from the server that responded the http request and I'm trying to avoid to make two calls (and possibly having a different ip address from the one that responded the request.
Is that possible? Does any python http library allows me to do that?
ps: I also need to make HTTPS requests and to use an authenticated proxy.
Update 1:
Example:
import requests
proxies = {
"http": "http://user:password@10.10.1.10:3128",
"https": "http://user:password@10.10.1.10:1080",
}
response = requests.get("http://example.org", proxies=proxies)
response.ip # This doesn't exist, this is just an what I would like to do
then, I would like to know to which IP address requests connected from a method or property in the response. In other libraries I was able to do that by finding the sock object and using the getpeername() method.
回答1:
It turns out that it's rather involved.
Here's a monkey-patch while using requests
version 1.2.3:
Wrapping the _make_request
method on HTTPConnectionPool
to store the response from socket.getpeername()
on the HTTPResponse
instance.
For me on python 2.7.3, this instance was available on response.raw._original_response
.
from requests.packages.urllib3.connectionpool import HTTPConnectionPool
def _make_request(self,conn,method,url,**kwargs):
response = self._old_make_request(conn,method,url,**kwargs)
sock = getattr(conn,'sock',False)
if sock:
setattr(response,'peer',sock.getpeername())
else:
setattr(response,'peer',None)
return response
HTTPConnectionPool._old_make_request = HTTPConnectionPool._make_request
HTTPConnectionPool._make_request = _make_request
import requests
r = requests.get('http://www.google.com')
print r.raw._original_response.peer
Yields:
('2a00:1450:4009:809::1017', 80, 0, 0)
Ah, if there's a proxy involved or the response is chunked, the HTTPConnectionPool._make_request
isn't called.
So here's a new version patching httplib.getresponse
instead:
import httplib
def getresponse(self,*args,**kwargs):
response = self._old_getresponse(*args,**kwargs)
if self.sock:
response.peer = self.sock.getpeername()
else:
response.peer = None
return response
httplib.HTTPConnection._old_getresponse = httplib.HTTPConnection.getresponse
httplib.HTTPConnection.getresponse = getresponse
import requests
def check_peer(resp):
orig_resp = resp.raw._original_response
if hasattr(orig_resp,'peer'):
return getattr(orig_resp,'peer')
Running:
>>> r1 = requests.get('http://www.google.com')
>>> check_peer(r1)
('2a00:1450:4009:808::101f', 80, 0, 0)
>>> r2 = requests.get('https://www.google.com')
>>> check_peer(r2)
('2a00:1450:4009:808::101f', 443, 0, 0)
>>> r3 = requests.get('http://wheezyweb.readthedocs.org/en/latest/tutorial.html#what-you-ll-build')
>>> check_peer(r3)
('162.209.99.68', 80)
Also checked running with proxies set; proxy address is returned.
Update 2016/01/19
est offers an alternative that doesn't need the monkey-patch:
rsp = requests.get('http://google.com', stream=True)
# grab the IP while you can, before you consume the body!!!!!!!!
print rsp.raw._fp.fp._sock.getpeername()
# consume the body, which calls the read(), after that fileno is no longer available.
print rsp.content
Update 2016/05/19
From the comments, copying here for visibility, Richard Kenneth Niescior offers the following that is confirmed working with requests 2.10.0 and Python 3.
rsp=requests.get(..., stream=True)
rsp.raw._connection.sock.getpeername()
Update 2019/02/22
Python3 with requests version 2.19.1.
rsp=requests.get(..., stream=True)
resp.raw._connection.sock.socket.getsockname()
来源:https://stackoverflow.com/questions/22492484/how-do-i-get-the-ip-address-from-a-http-request-using-the-requests-library