问题
I have the following codes:
if date in (start, end):
print 'in between'
else:
print 'No!'
date, start and end are all variables with the format of 1/1. What should I do to have it print out the right result? i tried date as 10/2, start as 3/14 and end as 11/7 and it's print 'No!', which means it's not running right. I guess have to format them to a date format and then compare them. Thanks for any help!
回答1:
As you are still not satisfied, I have another answer for you. Without using datetime and year.
It just uses built-in tuples and comparing them:
d1 = (3, 28)
d2 = (3, 31)
d3 = (4, 2)
if d1 < d2 < d3:
print("BETWEEN!")
else:
print("NOT!")
You can create tuple like these easily:
day = 16
month = 4
d = (month, day)
回答2:
If you convert all your dates to datetime.date, you can write the following:
if start <= date <= end:
print "in between"
else:
print "No!"
回答3:
Use datetime.date
:
http://docs.python.org/library/datetime.html#datetime.date
<
operator is overloaded specially for you.
date1 < date2
- date1 is considered less than date2 when date1 precedes date2 in time.
>>> from datetime import date
>>> d1 = date(2011, 3, 28)
>>> d2 = date(2011, 3, 22)
>>> d3 = date(2011, 4, 3)
>>> d2 < d1 < d3
True
Or in your prgram:
from datetime import date
d1 = date(2011, 3, 28)
d2 = date(2011, 3, 22)
d3 = date(2011, 4, 3)
if d2 < d1 < d3:
print 'in between'
else:
print 'No!'
回答4:
from datetime import datetime
date_format = "%m/%d/%Y"
a = datetime.strptime('8/18/2008', date_format)
b = datetime.strptime('9/26/2007', date_format) # Date to be checked
c = datetime.strptime('9/25/2008', date_format)
d = datetime.strptime('8/18/2008', date_format) #Date entered here should always be the same as 'a'
delta1 = b - a
delta2 = c - b
delta3 = d - a
if delta1.days >= delta3.days and delta2.days >= delta3.days:
print 'In between'
else:
print 'Not in between'
来源:https://stackoverflow.com/questions/5464410/how-to-tell-if-a-date-is-between-two-other-dates-in-python