问题
eg:
String s="this is a.line is .over "
should come out as
"This is a.Line is.Over"
I thought of using string tokenizer twice
-first split using"."
-second split using " " to get the first word
-then change charAt[0].toUpper
now i'm not sure how to use the output of string tokenizer as input for another?
also i can using the split method to generate array something i tried
String a="this is.a good boy";
String [] dot=a.split("\\.");
while(i<dot.length)
{
String [] sp=dot[i].split(" ");
sp[0].charAt(0).toUpperCase();// what to do with this part?
回答1:
Use StringBuilder, no need to split and create other strings, and so on, see the code
public static void main(String... args) {
String text = "this is a.line is. over";
int pos = 0;
boolean capitalize = true;
StringBuilder sb = new StringBuilder(text);
while (pos < sb.length()) {
if (sb.charAt(pos) == '.') {
capitalize = true;
} else if (capitalize && !Character.isWhitespace(sb.charAt(pos))) {
sb.setCharAt(pos, Character.toUpperCase(sb.charAt(pos)));
capitalize = false;
}
pos++;
}
System.out.println(sb.toString());
}
回答2:
No need to mess with splitting and splicing, you can work in-place on a character array:
String s = "this is a.line is .over ";
char[] cs = s.toCharArray();
// make sure to capitalise the first letter in the string
capitaliseNextLetter(cs, 0);
for (int i = 0; i < cs.length; i++) {
// look for a period
if (cs[i] == '.') {
// capitalise the first letter after the period
i = capitaliseNextLetter(cs, i);
// we're assigning to i to skip the characters that
// `capitaliseNextLetter()` already looked at.
}
}
System.out.println(new String(cs));
// This will capitalise the first letter in the array `cs` found after
// the index `i`
private static int capitaliseNextLetter(char[] cs, int i) {
for (; i < cs.length; i++) {
// This will skip any non-letter after the space. Adjust the test
// as desired
if (Character.isAlphabetic(cs[i])) {
cs[i] = Character.toUpperCase(cs[i]);
return i;
}
}
return cs.length;
}
回答3:
Try this to capitalize first letter of the sentence. I just did little changes in your code.
public static void main(String[] args) {
String a = "this is.a good boy";
String[] dot = a.split("\\.");
int i = 0;
String output = "";
while (i < dot.length) {
dot[i] = String.valueOf(dot[i].charAt(0)).toUpperCase()
+ dot[i].substring(1);
output = output + dot[i] + ".";
i++;
}
System.out.println(output);
}
Output:
This is.A good boy.
回答4:
If you can use WordUtils from Apache commons-lang3, do this:
WordUtils.capitalizeFully(text, '.')
回答5:
Note that Java Strings are immutable (not modifiable).
Also note that sp[0].charAt(0)
will cause an ArrayIndexOutOfBoundsException
if there's a space directly after a .
(since then the first string will be empty).
I suggest using char[]
, so something like:
String a = "this is.a good boy";
char arr[] = a.toCharArray();
boolean capitalize = true;
for (int i = 0; i < arr.length; i++)
if (arr[i] == '.')
capitalize = true;
else if (arr[i] != ' ' && capitalize)
{
arr[i] = Character.toUpperCase(arr[i]);
capitalize = false;
}
a = new String(arr);
Character.isWhitespace(arr[i])
may be preferred to arr[i] != ' '
.
回答6:
char[] strArr = str.toCharArray();
for (int i = 0; i < strArr.length; i++) {
if (str.charAt(i) == " ".charAt(0) && i + 1 < strArr.length) {
strArr[i + 1] = String.valueOf(String.valueOf(strArr[i + 1])).toUpperCase().charAt(0);
}
}
System.out.println(String.valueOf(strArr));
来源:https://stackoverflow.com/questions/16078479/capitalize-first-word-of-a-sentence-in-a-string-with-multiple-sentences