问题
I have a form that pops up on a user's screen and has TopMost=true
, but it steals the focus. How can I get it to not steal focus when it first appears?
回答1:
Paste this code in your form:
protected override bool ShowWithoutActivation
{
get { return true; }
}
回答2:
This is what worked for me. It provides TopMost but without focus-stealing.
protected override bool ShowWithoutActivation
{
get { return true; }
}
private const int WS_EX_TOPMOST = 0x00000008;
protected override CreateParams CreateParams
{
get
{
CreateParams createParams = base.CreateParams;
createParams.ExStyle |= WS_EX_TOPMOST;
return createParams;
}
}
Remember to omit setting TopMost in Visual Studio designer, or elsewhere.
This is stolen, err, borrowed, from here (click on Workarounds):
https://connect.microsoft.com/VisualStudio/feedback/details/401311/showwithoutactivation-is-not-supported-with-topmost
回答3:
You can do it like this:
private const int SW_SHOWNOACTIVATE = 4;
private const int HWND_TOPMOST = -1;
private const uint SWP_NOACTIVATE = 0x0010;
[System.Runtime.InteropServices.DllImport("user32.dll", EntryPoint = "SetWindowPos")]
private static extern bool SetWindowPos(
int hWnd, // Window handle
int hWndInsertAfter, // Placement-order handle
int X, // Horizontal position
int Y, // Vertical position
int cx, // Width
int cy, // Height
uint uFlags); // Window positioning flags
[System.Runtime.InteropServices.DllImport("user32.dll")]
private static extern bool ShowWindow(System.IntPtr hWnd, int nCmdShow);
public static void ShowInactiveTopmost(System.Windows.Forms.Form frm)
{
try
{
ShowWindow(frm.Handle, SW_SHOWNOACTIVATE);
SetWindowPos(frm.Handle.ToInt32(), HWND_TOPMOST,
frm.Left, frm.Top, frm.Width, frm.Height,
SWP_NOACTIVATE);
}
catch (System.Exception ex)
{
// error handling
}
}
回答4:
I tested the below code using a timer on form1 to instantiate and show form2 with form1 as owner.
In form2's Shown event I then set focus to the owner, which is the current active form.
I have a textbox on form1 and was able to continuesly write in the textbox without loosing focus during this process.
My timer code in form1:
private void timer1_Tick(object sender, EventArgs e)
{
Form2 popup = new Form2();
popup.TopMost = true;
popup.Show(this);
timer1.Enabled = false;
}
My code in the Shown event of form2:
private void Form2_Shown(object sender, EventArgs e)
{
this.Owner.Focus();
}
You can do this or simply set TopMost to false and use the override of ShowWithoutActivation as Hans Passant stated.
Edit: (Or use p/invoke as seen in Hans Passant's additional comment I missed while I wrote this)
回答5:
I came across the same problem. I'm not using C# but C++. I figure this could be useful anyways:
Using windows.h:
BOOL WINAPI SetWindowPos(
__in HWND hWnd,
__in_opt HWND hWndInsertAfter,
__in int X,
__in int Y,
__in int cx,
__in int cy,
__in UINT uFlags
);
Passing the flag SWP_NOACTIVATE to the uFlags argument worked for me.
回答6:
You can set:
this.TopMost = True;
on Load event of that form.
It's OK with me!
回答7:
Instead of writing .setfocus()
in _activated
event; write it to .shown
event of the form.
来源:https://stackoverflow.com/questions/3729899/opening-a-winforms-form-with-topmost-true-but-not-having-it-steal-focus