NameError: name 'self' is not defined

问题

Why such structure

class A:
    def __init__(self, a):
        self.a = a

    def p(self, b=self.a):
        print b

gives an error NameError: name 'self' is not defined?

回答1:

Default argument values are evaluated at function define-time, but self is an argument only available at function call time. Thus arguments in the argument list cannot refer each other.

It's a common pattern to default an argument to None and add a test for that in code:

def p(self, b=None):
    if b is None:
        b = self.a
    print b

回答2:

For cases where you also wish to have the option of setting 'b' to None:

def p(self, **kwargs):
    b = kwargs.get('b', self.a)
    print b

回答3:

If you have arrived here via google, please make sure to check that you have given self as the first parameter to a class function. Especially if you try to reference values for that object inside the function.

def foo():
    print(self.bar)

>NameError: name 'self' is not defined

def foo(self):
    print(self.bar)

>"Congrats you got rid of the NameError!"

来源：https://stackoverflow.com/questions/1802971/nameerror-name-self-is-not-defined