问题
This seems fairly simple but I can't get it to turn up on Google.
If I have:
class City < ActiveRecord::Base
has_many :photos
end
class Photo < ActiveRecord::Base
belongs_to :city
end
I want to find all cities that have no photos. I'd love to be able to call something like...
City.where( photos.empty? )
...but that doesn't exist. So, how do you do this kind of query?
Update: Having now found an answer to the original question, I'm curious, how do you construct the inverse?
IE: if I wanted to create these as scopes:
scope :without_photos, includes(:photos).where( :photos => {:city_id=>nil} )
scope :with_photos, ???
回答1:
Bah, found it here: https://stackoverflow.com/a/5570221/417872
City.includes(:photos).where(photos: { city_id: nil })
回答2:
In Rails 5, to find all cities that have no photos, you can use left_outer_joins:
City.left_outer_joins(:photos).where(photos: {id: nil})
which will result in SQL like:
SELECT cities.*
FROM cities LEFT OUTER JOIN photos ON photos.city_id = city.id
WHERE photos.id IS NULL
Using includes:
City.includes(:photos).where(photos: {id: nil})
will have the same result, but will result in much uglier SQL like:
SELECT cities.id AS t0_r0, cities.attr1 AS t0_r1, cities.attr2 AS t0_r2, cities.created_at AS t0_r3, cities.updated_at AS t0_r4, photos.id AS t1_r0, photos.city_id AS t1_r1, photos.attr1 AS t1_r2, photos.attr2 AS t1_r3, photos.created_at AS t1_r4, photos.updated_at AS t1_r5
FROM cities LEFT OUTER JOIN photos ON photos.city_id = cities.id
WHERE photos.id IS NULL
回答3:
When trying to find records with no matching records from the joined table, you need to use a LEFT OUTER JOIN
scope :with_photos, joins('LEFT OUTER JOIN photos ON cities.id = photos.city_id').group('cities.id').having('count(photos.id) > 0')
scope :without_photos, joins('LEFT OUTER JOIN photos ON cities.id = photos.city_id').group('cities.id').having('count(photos.id) = 0')
回答4:
I used a join to get all the ones with photos:
scope :with_photos, -> { joins(:photos).distinct }
Easier to write and understand, for that particular case. I'm not sure what the efficiency is of doing a join vs doing an includes, though
回答5:
I don't believe the accepted answer gives you exactly what you're looking for, as you want to do a LEFT OUTER JOIN
and that answer will give you a INNER JOIN
. At least in Rails 5 you can use:
scope :without_photos, left_joins(:photos).where( photos: {id: nil} )
or you can use merge
in cases where namespacing will make the where
clause cumbersome:
scope :without_photos, left_joins(:photos).merge( Photos.where(id: nil) )
回答6:
If you are not running Rails 5+ and performance is a must-have, avoid useless ActiveRecord creation and get just what you need:
City.where("NOT EXISTS(SELECT 1 FROM photos WHERE photos.city_id = cities.id LIMIT 1)")
来源:https://stackoverflow.com/questions/9613717/rails-find-record-with-zero-has-many-records-associated