问题
I'm trying to do something like this. But I get an unknown column error:
SELECT SUM(field1 + field2) AS col1, col1 + field3 AS col3 from core
Basically, I want to just use the alias so that I won't need to perform the operations performed earlier. Is this possible in mysql?
回答1:
Consider using a subquery, like:
SELECT col1
, col1 + field3 AS col3
FROM (
SELECT field1 + field2 as col1
, field3
from core
) as SubQueryAlias
回答2:
select @code:= SUM(field1 + field2), @code+1 from abc;
But, please be aware of the following (from the MySQL 5.6 docs):
As a general rule, other than in SET statements, you should never assign a value to a user variable and read the value within the same statement. For example, to increment a variable, this is okay:
SET @a = @a + 1;
For other statements, such as SELECT, you might get the results you expect, but this is not guaranteed. In the following statement, you might think that MySQL will evaluate @a first and then do an assignment second:
SELECT @a, @a:=@a+1, ...;
However, the order of evaluation for expressions involving user variables is undefined.
So, use at your own risk.
回答3:
You can select
the alias:
SELECT SUM(field1 + field2) AS col1, (select col1) + field3 AS col3 from core
This works.
回答4:
According to the spec Ravi Parekh's answer is not guaranteed to always work, as "order of evaluation for expressions involving user variables is undefined".
I found this answer after I tried to use a variable and got weird results.
回答5:
select @code:= SUM(field1 + field2), (@code*1) from abc;
@code*1 covert into numeric expression and you can use anywhere like
select @code:= SUM(field1 + field2), (@code*1)+field3 from abc;
回答6:
Short answer is no:
mysql> select 1 as a, a + 1 as b;
ERROR 1054 (42S22): Unknown column 'a' in 'field list'
postgresql# select 1 as a, a + 1 as b;
ERROR: column "a" does not exist
That said, some SQL implementations allow to use the aliases in where/group by/having clauses, e.g.:
postgresql# select 1 as a group by a; -- 1 row
回答7:
In case you are using it with aggregate function (group by) and if it doesn't work for you place the calculated column to the end with forward column referecing.
SELECT FNC2(AF), FNC1(A) AS AF, B, C, FROM Table GROUP BY ...
1st one doesn't work due to forward column referencing. Do this instead
SELECT FNC1(A) AS AF, B, C, FNC2((SELECT AF)) FROM Table GROUP BY ...
来源:https://stackoverflow.com/questions/6081436/how-to-alias-a-field-or-column-in-mysql