How to force input to only allow Alpha Letters?

与世无争的帅哥 提交于 2019-12-17 06:41:42

问题


using jQuery here, however unable to prevent numbers from being typed into the input field

http://codepen.io/leongaban/pen/owbjg

Input

<input type="text" name="field" maxlength="8"
    title="Only Letters"
    value="Type Letters Only"
    onkeydown="return alphaOnly(event);"
    onblur="if (this.value == '') {this.value = 'Type Letters Only';}"
    onfocus="if (this.value == 'Type Letters Only') {this.value = '';}"/>

jQuery

function alphaOnly(event) {

  alert(event);

  var key;

  if (window.event) {
    key = window.event.key;
  } else if (e) {
    key = e.which;
  }
  //var key = window.event.key || event.key;
  alert(key.value);
  return ((key >= 65 && key <= 90) || (key >= 95 && key <= 122));

}

I've seen plenty of examples here on how to restrict to only Numbers, and I'm using the correct key codes for a-z and A-Z. Do you see what I'm doing wrong?


回答1:


The property event.key gave me an undefined value. Instead, I used event.keyCode:

function alphaOnly(event) {
  var key = event.keyCode;
  return ((key >= 65 && key <= 90) || key == 8);
};

Note that the value of 8 is for the backspace key.




回答2:


Rather than relying on key codes, which can be quite cumbersome, you can instead use regular expressions. By changing the pattern we can easily restrict the input to fit our needs. Note that this works with the keypress event and will allow the use of backspace (as in the accepted answer). It will not prevent users from pasting 'illegal' chars.

function testInput(event) {
   var value = String.fromCharCode(event.which);
   var pattern = new RegExp(/[a-zåäö ]/i);
   return pattern.test(value);
}

$('#my-field').bind('keypress', testInput);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<label>
   Test input:
   <input id="my-field" type="text">
</label>



回答3:


Short ONELINER:

<input onkeypress="return /[a-z]/i.test(event.key)" >

For all unicode letters try this regexp: /\p{L}/u (but ... this) - and here is working example :)




回答4:


On newer browsers, you can use:

<input type="text" name="country_code" 
    pattern="[A-Za-z]" title="Three letter country code">

You can use regular expressions to restrict the input fields.




回答5:


Nice one-liner HTML only:

 <input type="text" id='nameInput' onkeypress='return ((event.charCode >= 65 && event.charCode <= 90) || (event.charCode >= 97 && event.charCode <= 122) || (event.charCode == 32))'>



回答6:


<input type="text" name="field" maxlength="8"
    onkeypress="return onlyAlphabets(event,this);" />

function onlyAlphabets(e, t) {
            try {
                if (window.event) {
                    var charCode = window.event.keyCode;
                }
                else if (e) {
                    var charCode = e.which;
                }
                else { return true; }
                if ((charCode > 64 && charCode < 91) || (charCode > 96 && charCode < 123))
                    return true;
                else
                    return false;
            }
            catch (err) {
                alert(err.Description);
            }
        }



回答7:


A lot of the other solutions that use keypress will not work on mobile, you need to use input.

html

<input type="text" id="name"  data-value="" autocomplete="off" spellcheck="true" placeholder="Type your name" autofocus />

jQuery

$('#name').on('input', function() {
    var cursor_pos = $(this).getCursorPosition()
    if(!(/^[a-zA-Z ']*$/.test($(this).val())) ) {
        $(this).val($(this).attr('data-value'))
        $(this).setCursorPosition(cursor_pos - 1)
        return
    }
    $(this).attr('data-value', $(this).val())
})

$.fn.getCursorPosition = function() {
    if(this.length == 0) return -1
    return $(this).getSelectionStart()
}
$.fn.setCursorPosition = function(position) {
    if(this.lengh == 0) return this
    return $(this).setSelection(position, position)
}
$.fn.getSelectionStart = function(){
  if(this.lengh == 0) return -1
  input = this[0]
  var pos = input.value.length
  if (input.createTextRange) {
    var r = document.selection.createRange().duplicate()
    r.moveEnd('character', input.value.length)
    if (r.text == '') 
    pos = input.value.length
    pos = input.value.lastIndexOf(r.text)
  } else if(typeof(input.selectionStart)!="undefined")
  pos = input.selectionStart
  return pos
}
$.fn.setSelection = function(selectionStart, selectionEnd) {
  if(this.lengh == 0) return this
  input = this[0]
  if(input.createTextRange) {
    var range = input.createTextRange()
    range.collapse(true)
    range.moveEnd('character', selectionEnd)
    range.moveStart('character', selectionStart)
    range.select()
  }
  else if (input.setSelectionRange) {
    input.focus()
    input.setSelectionRange(selectionStart, selectionEnd)
  }
  return this
}



回答8:


<input type="text" name="name" id="event" onkeydown="return alphaOnly(event);"   required />


function alphaOnly(event) {
  var key = event.keyCode;`enter code here`
  return ((key >= 65 && key <= 90) || key == 8);
};


来源:https://stackoverflow.com/questions/19508183/how-to-force-input-to-only-allow-alpha-letters

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!