问题
I am trying to use javascript's split to get the sentences out of a string but keep the delimiter eg !?.
So far I have
sentences = text.split(/[\\.!?]/);
which works but does not include the ending punctuation for each sentence (.!?).
Does anyone know of a way to do this?
回答1:
You need to use match not split.
Try this.
var str = "I like turtles. Do you? Awesome! hahaha. lol!!! What's going on????";
var result = str.match( /[^\.!\?]+[\.!\?]+/g );
var expect = ["I like turtles.", " Do you?", " Awesome!", " hahaha.", " lol!!!", " What's going on????"];
console.log( result.join(" ") === expect.join(" ") )
console.log( result.length === 6);
回答2:
The following is a small addition to Larry's answer which will match also paranthetical sentences:
text.match(/\(?[^\.\?\!]+[\.!\?]\)?/g);
applied on:
text = "If he's restin', I'll wake him up! (Shouts at the cage.)
'Ello, Mister Polly Parrot! (Owner hits the cage.) There, he moved!!!"
giveth:
["If he's restin', I'll wake him up!", " (Shouts at the cage.)",
" 'Ello, Mister Polly Parrot!", " (Owner hits the cage.)", " There, he moved!!!"]
回答3:
Try this instead:-
sentences = text.split(/[\\.!\?]/);
? is a special char in regular expressions so need to be escaped.
Sorry I miss read your question - if you want to keep delimiters then you need to use match not split see this question
回答4:
A slight improvement on mircealungu's answer:
string.match(/[^.?!]+[.!?]+[\])'"`’”]*/g);
- There's no need for the opening parenthesis at the beginning.
- Punctuation like
'...','!!!','!?'etc. are included inside sentences. - Any number of square close brackets and close parentheses are included. [Edit: different closing quotation marks added]
来源：https://stackoverflow.com/questions/11761563/javascript-regexp-for-splitting-text-into-sentences-and-keeping-the-delimiter