问题
Is there a simple library to benchmark the time it takes to execute a portion of C code? What I want is something like:
int main(){
benchmarkBegin(0);
//Do work
double elapsedMS = benchmarkEnd(0);
benchmarkBegin(1)
//Do some more work
double elapsedMS2 = benchmarkEnd(1);
double speedup = benchmarkSpeedup(elapsedMS, elapsedMS2); //Calculates relative speedup
}
It would also be great if the library let you do many runs, averaging them and calculating the variance in timing!
回答1:
Basically, all you want is a high resolution timer. The elapsed time is of course just a difference in times and the speedup is calculated by dividing the times for each task. I have included the code for a high resolution timer that should work on at least windows and unix.
#ifdef WIN32
#include <windows.h>
double get_time()
{
LARGE_INTEGER t, f;
QueryPerformanceCounter(&t);
QueryPerformanceFrequency(&f);
return (double)t.QuadPart/(double)f.QuadPart;
}
#else
#include <sys/time.h>
#include <sys/resource.h>
double get_time()
{
struct timeval t;
struct timezone tzp;
gettimeofday(&t, &tzp);
return t.tv_sec + t.tv_usec*1e-6;
}
#endif
回答2:
Use the function clock()
defined in time.h
:
startTime = (float)clock()/CLOCKS_PER_SEC;
/* Do work */
endTime = (float)clock()/CLOCKS_PER_SEC;
timeElapsed = endTime - startTime;
回答3:
In POSIX, try getrusage. The relevant argument is RUSAGE_SELF and the relevant fields are ru_utime.tv_sec and ru_utime.tv_usec.
回答4:
There may be existing utilities that help with this, but I suspect most will use some kind of sampling or possibly injection. But to get specific sections of code timed, you will probably have to add in calls to a timer like you show in your example. If you are using Windows, then the high performance timer works. I answered a similar question and showed example code that will do that. There are similar methods for Linux.
来源:https://stackoverflow.com/questions/2349776/how-can-i-benchmark-c-code-easily