jQuery hasClass() - check for more than one class

问题

With:

if(element.hasClass("class"))

I can check for one class, but is there an easy way to check whether "element" has any of many classes?

I am using:

if(element.hasClass("class") || element.hasClass("class") ... )

Which isn't too bad, but I am thinking of something like:

if(element.hasClass("class", "class2")

Which unfortunately doesn't work.

Is there something like that?

回答1:

How about:

element.is('.class1, .class2')

回答2:

element.is('.class1, .class2')

works, but it's 35% slower than

element.hasClass('class1') || element.hasClass('class2')

If you doubt what i say, you can verify on jsperf.com.

Hope this help someone.

回答3:

$.fn.extend({
    hasClasses: function (selectors) {
        var self = this;
        for (var i in selectors) {
            if ($(self).hasClass(selectors[i])) 
                return true;
        }
        return false;
    }
});

$('#element').hasClasses(['class1', 'class2', 'class3']);

This should do it, simple and easy.

回答4:

filter() is another option

Reduce the set of matched elements to those that match the selector or pass the function's test.

$(selector).filter('.class1, .class2'); //Filter elements: class1 OR class2

$(selector).filter('.class1.class2'); // Filter elements: class1 AND class2

回答5:

How about this?

if (element.hasClass("class1 class2")

回答6:

here's an answer that does follow the syntax of

$(element).hasAnyOfClasses("class1","class2","class3")

(function($){
    $.fn.hasAnyOfClasses = function(){
        for(var i= 0, il=arguments.length; i<il; i++){
            if($self.hasClass(arguments[i])) return true;
        }
        return false;
    }
})(jQuery);

it's not the fastest, but its unambiguous and the solution i prefer. bench: http://jsperf.com/hasclasstest/10

回答7:

What about this,

$.fn.extend({
     hasClasses: function( selector ) {
        var classNamesRegex = new RegExp("( " + selector.replace(/ +/g,"").replace(/,/g, " | ") + " )"),
            rclass = /[\n\t\r]/g,
            i = 0,
            l = this.length;
        for ( ; i < l; i++ ) {
            if ( this[i].nodeType === 1 && classNamesRegex.test((" " + this[i].className + " ").replace(rclass, " "))) {
                return true;
            }
        }
        return false;
    }
});

Easy to use,

if ( $("selector").hasClasses("class1, class2, class3") ) {
  //Yes It does
}

And It seems to be faster, http://jsperf.com/hasclasstest/7

回答8:

What about:

if($('.class.class2.class3').length > 0){
    //...
}

回答9:

use default js match() function:

if( element.attr('class') !== undefined && element.attr('class').match(/class1|class2|class3|class4|class5/) ) {
  console.log("match");
}

to use variables in regexp, use this:

var reg = new RegExp(variable, 'g');
$(this).match(reg);

by the way, this is the fastest way: http://jsperf.com/hasclass-vs-is-stackoverflow/22

回答10:

Works for me:

 if ( $("element").hasClass( "class1") || $("element").hasClass("class2") ) {

 //do something here

 }

回答11:

You can do this way:

if($(selector).filter('.class1, .class2').length){
    // Or logic
}

if($(selector).filter('.class1, .class2').length){
    // And logic
}

回答12:

This worked for me:

$('.class1[class~="class2"]').append('something');

来源：https://stackoverflow.com/questions/2214952/jquery-hasclass-check-for-more-than-one-class