问题
My problem is that I wish to return camelCased (as opposed to the standard PascalCase) JSON data via ActionResults from ASP.NET MVC controller methods, serialized by JSON.NET.
As an example consider the following C# class:
public class Person
{
public string FirstName { get; set; }
public string LastName { get; set; }
}
By default, when returning an instance of this class from an MVC controller as JSON, it'll be serialized in the following fashion:
{
"FirstName": "Joe",
"LastName": "Public"
}
I would like it to be serialized (by JSON.NET) as:
{
"firstName": "Joe",
"lastName": "Public"
}
How do I do this?
回答1:
or, simply put:
JsonConvert.SerializeObject(
<YOUR OBJECT>,
new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
});
For instance:
return new ContentResult
{
ContentType = "application/json",
Content = JsonConvert.SerializeObject(new { content = result, rows = dto }, new JsonSerializerSettings { ContractResolver = new CamelCasePropertyNamesContractResolver() }),
ContentEncoding = Encoding.UTF8
};
回答2:
I found an excellent solution to this problem on Mats Karlsson's blog. The solution is to write a subclass of ActionResult that serializes data via JSON.NET, configuring the latter to follow the camelCase convention:
public class JsonCamelCaseResult : ActionResult
{
public JsonCamelCaseResult(object data, JsonRequestBehavior jsonRequestBehavior)
{
Data = data;
JsonRequestBehavior = jsonRequestBehavior;
}
public Encoding ContentEncoding { get; set; }
public string ContentType { get; set; }
public object Data { get; set; }
public JsonRequestBehavior JsonRequestBehavior { get; set; }
public override void ExecuteResult(ControllerContext context)
{
if (context == null)
{
throw new ArgumentNullException("context");
}
if (JsonRequestBehavior == JsonRequestBehavior.DenyGet && String.Equals(context.HttpContext.Request.HttpMethod, "GET", StringComparison.OrdinalIgnoreCase))
{
throw new InvalidOperationException("This request has been blocked because sensitive information could be disclosed to third party web sites when this is used in a GET request. To allow GET requests, set JsonRequestBehavior to AllowGet.");
}
var response = context.HttpContext.Response;
response.ContentType = !String.IsNullOrEmpty(ContentType) ? ContentType : "application/json";
if (ContentEncoding != null)
{
response.ContentEncoding = ContentEncoding;
}
if (Data == null)
return;
var jsonSerializerSettings = new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
};
response.Write(JsonConvert.SerializeObject(Data, jsonSerializerSettings));
}
}
Then use this class as follows in your MVC controller method:
public ActionResult GetPerson()
{
return new JsonCamelCaseResult(new Person { FirstName = "Joe", LastName = "Public" }, JsonRequestBehavior.AllowGet)};
}
回答3:
For WebAPI, check out this link: http://odetocode.com/blogs/scott/archive/2013/03/25/asp-net-webapi-tip-3-camelcasing-json.aspx
Basically, add this code to your Application_Start:
var formatters = GlobalConfiguration.Configuration.Formatters;
var jsonFormatter = formatters.JsonFormatter;
var settings = jsonFormatter.SerializerSettings;
settings.ContractResolver = new CamelCasePropertyNamesContractResolver();
回答4:
I think this is the simple answer you are looking for. It's from Shawn Wildermuth's blog:
// Add MVC services to the services container.
services.AddMvc()
.AddJsonOptions(opts =>
{
opts.SerializerSettings.ContractResolver = new CamelCasePropertyNamesContractResolver();
});
回答5:
An alternative to the custom filter is to create an extension method to serialize any object to JSON.
public static class ObjectExtensions
{
/// <summary>Serializes the object to a JSON string.</summary>
/// <returns>A JSON string representation of the object.</returns>
public static string ToJson(this object value)
{
var settings = new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver(),
Converters = new List<JsonConverter> { new StringEnumConverter() }
};
return JsonConvert.SerializeObject(value, settings);
}
}
Then call it when returning from the controller action.
return Content(person.ToJson(), "application/json");
回答6:
In ASP.NET Core MVC.
public IActionResult Foo()
{
var data = GetData();
var settings = new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
});
return Json(data, settings);
}
回答7:
Simpler is better IMO!
Why don't you do this?
public class CourseController : JsonController
{
public ActionResult ManageCoursesModel()
{
return JsonContent(<somedata>);
}
}
The simple base class controller
public class JsonController : BaseController
{
protected ContentResult JsonContent(Object data)
{
return new ContentResult
{
ContentType = "application/json",
Content = JsonConvert.SerializeObject(data, new JsonSerializerSettings {
ContractResolver = new CamelCasePropertyNamesContractResolver() }),
ContentEncoding = Encoding.UTF8
};
}
}
回答8:
Below is an action method that returns a json string (cameCase) by serializing an array of objects.
public string GetSerializedCourseVms()
{
var courses = new[]
{
new CourseVm{Number = "CREA101", Name = "Care of Magical Creatures", Instructor ="Rubeus Hagrid"},
new CourseVm{Number = "DARK502", Name = "Defence against dark arts", Instructor ="Severus Snape"},
new CourseVm{Number = "TRAN201", Name = "Transfiguration", Instructor ="Minerva McGonal"}
};
var camelCaseFormatter = new JsonSerializerSettings();
camelCaseFormatter.ContractResolver = new CamelCasePropertyNamesContractResolver();
return JsonConvert.SerializeObject(courses, camelCaseFormatter);
}
Note the JsonSerializerSettings instance passed as the second parameter. That's what makes the camelCase happen.
回答9:
I did like this :
public static class JsonExtension
{
public static string ToJson(this object value)
{
var settings = new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver(),
NullValueHandling = NullValueHandling.Ignore,
ReferenceLoopHandling = ReferenceLoopHandling.Serialize
};
return JsonConvert.SerializeObject(value, settings);
}
}
this a simple extension method in MVC core , it's going to give the ToJson() ability to every object in your project , In my opinion in a MVC project most of object should have the ability to become json ,off course it depends :)
回答10:
You must set the settings in the file 'Startup.cs'
You also have to define it in the default values of JsonConvert, this is if you later want to directly use the library to serialize an object.
public void ConfigureServices(IServiceCollection services)
{
services.AddMvc().SetCompatibilityVersion(CompatibilityVersion.Version_2_2)
.AddJsonOptions(options => {
options.SerializerSettings.NullValueHandling = NullValueHandling.Ignore;
options.SerializerSettings.ContractResolver = new CamelCasePropertyNamesContractResolver();
});
JsonConvert.DefaultSettings = () => new JsonSerializerSettings
{
NullValueHandling = NullValueHandling.Ignore,
ContractResolver = new CamelCasePropertyNamesContractResolver()
};
}
来源：https://stackoverflow.com/questions/19445730/how-can-i-return-camelcase-json-serialized-by-json-net-from-asp-net-mvc-controll