How to clone a struct storing a boxed trait object?

问题

I wrote a program that has the trait Animal and the struct Dog implementing the trait. It also has a struct AnimalHouse storing an animal as a trait object Box<Animal>.

trait Animal {
    fn speak(&self);
}

struct Dog {
    name: String,
}

impl Dog {
    fn new(name: &str) -> Dog {
        return Dog {
            name: name.to_string(),
        };
    }
}

impl Animal for Dog {
    fn speak(&self) {
        println!{"{}: ruff, ruff!", self.name};
    }
}

struct AnimalHouse {
    animal: Box<Animal>,
}

fn main() {
    let house = AnimalHouse {
        animal: Box::new(Dog::new("Bobby")),
    };
    house.animal.speak();
}

It returns "Bobby: ruff, ruff!" as expected, but if I try to clone house the compiler returns errors:

fn main() {
    let house = AnimalHouse {
        animal: Box::new(Dog::new("Bobby")),
    };
    let house2 = house.clone();
    house2.animal.speak();
}

error[E0599]: no method named `clone` found for type `AnimalHouse` in the current scope
  --> src/main.rs:31:24
   |
23 | struct AnimalHouse {
   | ------------------ method `clone` not found for this
...
31 |     let house2 = house.clone();
   |                        ^^^^^
   |
   = help: items from traits can only be used if the trait is implemented and in scope
   = note: the following trait defines an item `clone`, perhaps you need to implement it:
           candidate #1: `std::clone::Clone`

I tried to add #[derive(Clone)] before struct AnimalHouse and got another error:

error[E0277]: the trait bound `Animal: std::clone::Clone` is not satisfied
  --> src/main.rs:25:5
   |
25 |     animal: Box<Animal>,
   |     ^^^^^^^^^^^^^^^^^^^ the trait `std::clone::Clone` is not implemented for `Animal`
   |
   = note: required because of the requirements on the impl of `std::clone::Clone` for `std::boxed::Box<Animal>`
   = note: required by `std::clone::Clone::clone`

How do I make the struct AnimalHouse cloneable? Is it idiomatic Rust to use a trait object actively, in general?

回答1:

There are a few problems. The first is that there's nothing to require that an Animal also implements Clone. You could fix this by changing the trait definition:

trait Animal: Clone {
    /* ... */
}

This would cause Animal to no longer be object safe, meaning that Box<Animal> will become invalid, so that's not great.

What you can do is insert an additional step. To whit (with additions from @ChrisMorgan's comment).

trait Animal: AnimalClone {
    fn speak(&self);
}

// Splitting AnimalClone into its own trait allows us to provide a blanket
// implementation for all compatible types, without having to implement the
// rest of Animal.  In this case, we implement it for all types that have
// 'static lifetime (*i.e.* they don't contain non-'static pointers), and
// implement both Animal and Clone.  Don't ask me how the compiler resolves
// implementing AnimalClone for Animal when Animal requires AnimalClone; I
// have *no* idea why this works.
trait AnimalClone {
    fn clone_box(&self) -> Box<Animal>;
}

impl<T> AnimalClone for T
where
    T: 'static + Animal + Clone,
{
    fn clone_box(&self) -> Box<Animal> {
        Box::new(self.clone())
    }
}

// We can now implement Clone manually by forwarding to clone_box.
impl Clone for Box<Animal> {
    fn clone(&self) -> Box<Animal> {
        self.clone_box()
    }
}

#[derive(Clone)]
struct Dog {
    name: String,
}

impl Dog {
    fn new(name: &str) -> Dog {
        Dog {
            name: name.to_string(),
        }
    }
}

impl Animal for Dog {
    fn speak(&self) {
        println!("{}: ruff, ruff!", self.name);
    }
}

#[derive(Clone)]
struct AnimalHouse {
    animal: Box<Animal>,
}

fn main() {
    let house = AnimalHouse {
        animal: Box::new(Dog::new("Bobby")),
    };
    let house2 = house.clone();
    house2.animal.speak();
}

By introducing clone_box, we can get around the problems with attempting to clone a trait object.

回答2:

My objekt crate implements a reusable version of DK.'s answer. With it you can make your original code work with a bare minimum of changes.

One line to import the crate.
One line to add objekt::Clone as a supertrait of Animal, requiring every animal implementation to be clonable.
One line to generate an implementation of the standard library Clone for Box<Animal>.

#[macro_use] extern crate objekt;

trait Animal: objekt::Clone {
    fn speak(&self);
}

clone_trait_object!(Animal);

#[derive(Clone)]
struct Dog {
    name: String,
}

impl Dog {
    fn new(name: &str) -> Dog {
        Dog { name: name.to_owned() }
    }
}

impl Animal for Dog {
    fn speak(&self) {
        println!{"{}: ruff, ruff!", self.name};
    }
}

#[derive(Clone)]
struct AnimalHouse {
    animal: Box<Animal>,
}

fn main() {
    let house = AnimalHouse {
        animal: Box::new(Dog::new("Bobby")),
    };
    let house2 = house.clone();
    house2.animal.speak();
}

回答3:

The previous answer correctly answers the question about storing a boxed trait object.

Getting off topic with respect to the title, but not about the idiomatic way of using trait objects, an alternative solution could be use the Rc smart pointer instead of a Box: this avoids the workaround for getting around object safety:

#[derive(Clone)]
struct AnimalHouse {
    animal: Rc<Animal>,
}

fn main() {
    let house = AnimalHouse { animal: Rc::new(Dog::new("Bobby")) };
    let house2 = house.clone();
    house2.animal.speak();
}

Note: Rc<T> is only for use in single-threaded scenarios; there's also Arc<T>.

来源：https://stackoverflow.com/questions/30353462/how-to-clone-a-struct-storing-a-boxed-trait-object

标签

struct

clone

rust

traits

cloneable