问题
I am using an AJAX-based lookup for names that a user searches in a text box.
I am making the assumption that all names in the database will be transliterated to European alphabets (i.e. no Cyrillic, Japanese, Chinese). However, the names will still contain accented characters, such as ç, ê and even č and ć.
A simple search like "Micic" will not match "Mičić" though - and the user expectation is that it will.
The AJAX lookup uses regular expressions to determine a match. I have modified the regular expression comparison using this function in an attempt to match more accented characters. However, it's a little clumsy since it doesn't take into account all characters.
function makeComp (input)
{
input = input.toLowerCase ();
var output = '';
for (var i = 0; i < input.length; i ++)
{
if (input.charAt (i) == 'a')
output = output + '[aàáâãäåæ]'
else if (input.charAt (i) == 'c')
output = output + '[cç]';
else if (input.charAt (i) == 'e')
output = output + '[eèéêëæ]';
else if (input.charAt (i) == 'i')
output = output + '[iìíîï]';
else if (input.charAt (i) == 'n')
output = output + '[nñ]';
else if (input.charAt (i) == 'o')
output = output + '[oòóôõöø]';
else if (input.charAt (i) == 's')
output = output + '[sß]';
else if (input.charAt (i) == 'u')
output = output + '[uùúûü]';
else if (input.charAt (i) == 'y')
output = output + '[yÿ]'
else
output = output + input.charAt (i);
}
return output;
}
Apart from a substitution function like this, is there a better way? Perhaps to "deaccent" the string being compared?
回答1:
There is a way to “"deaccent" the string being compared” without the use of a substitution function that lists all the accents you want to remove…
Here is the easiest solution I can think about to remove accents (and other diacritics) from a string.
See it in action:
var string = "Ça été Mičić. ÀÉÏÓÛ";
console.log(string);
var string_norm = string.normalize('NFD').replace(/[\u0300-\u036f]/g, "");
console.log(string_norm);回答2:
Came upon this old thread and thought I'd try my hand at doing a fast function. I'm relying on the ordering of pipe-separated ORs setting variables when they match in the function replace() is calling. My goal was to use the standard regex-implementation javascript's replace() function uses as much as possible, so that the heavy-processing can take place in low-level browser-optimized space, instead of in expensive javascript char-by-char comparisons.
It's not scientific at all, but my old Huawei IDEOS android phone is sluggish when I plug the other functions in this thread in to my autocomplete, while this function zips along:
function accentFold(inStr) {
return inStr.replace(
/([àáâãäå])|([çčć])|([èéêë])|([ìíîï])|([ñ])|([òóôõöø])|([ß])|([ùúûü])|([ÿ])|([æ])/g,
function (str, a, c, e, i, n, o, s, u, y, ae) {
if (a) return 'a';
if (c) return 'c';
if (e) return 'e';
if (i) return 'i';
if (n) return 'n';
if (o) return 'o';
if (s) return 's';
if (u) return 'u';
if (y) return 'y';
if (ae) return 'ae';
}
);
}
If you're a jQuery dev, here's a handy example of using this function; you could use :icontains the same way you'd use :contains in a selector:
jQuery.expr[':'].icontains = function (obj, index, meta, stack) {
return accentFold(
(obj.textContent || obj.innerText || jQuery(obj).text() || '').toLowerCase()
)
.indexOf(accentFold(meta[3].toLowerCase())
) >= 0;
};
回答3:
There is no easier way to "deaccent" that I can think of, but your substitution could be streamlined a little more:
var makeComp = (function(){
var accents = {
a: 'àáâãäåæ',
c: 'ç',
e: 'èéêëæ',
i: 'ìíîï',
n: 'ñ',
o: 'òóôõöø',
s: 'ß',
u: 'ùúûü',
y: 'ÿ'
},
chars = /[aceinosuy]/g;
return function makeComp(input) {
return input.replace(chars, function(c){
return '[' + c + accents[c] + ']';
});
};
}());
回答4:
I searched and upvoted herostwist answer but kept searching and truly, here is a modern solution, core to JavaScript (string.localeCompare function)
var a = 'réservé'; // with accents, lowercase
var b = 'RESERVE'; // no accents, uppercase
console.log(a.localeCompare(b));
// expected output: 1
console.log(a.localeCompare(b, 'en', {sensitivity: 'base'}));
// expected output: 0
NOTE, however, that full support is still missing for some mobile browser !!!
Until then, keep watching out for full support across ALL platforms and env.
Is that all ?
No, we can go further right now and use string.toLocaleLowerCase function.
var dotted = 'İstanbul';
console.log('EN-US: ' + dotted.toLocaleLowerCase('en-US'));
// expected output: "istanbul"
console.log('TR: ' + dotted.toLocaleLowerCase('tr'));
// expected output: "istanbul"
Thank You !
回答5:
I made a Prototype Version of this:
String.prototype.strip = function() {
var translate_re = /[öäüÖÄÜß ]/g;
var translate = {
"ä":"a", "ö":"o", "ü":"u",
"Ä":"A", "Ö":"O", "Ü":"U",
" ":"_", "ß":"ss" // probably more to come
};
return (this.replace(translate_re, function(match){
return translate[match];})
);
};
Use like:
var teststring = 'ä ö ü Ä Ö Ü ß';
teststring.strip();
This will will change the String to a_o_u_A_O_U_ss
回答6:
I think this is the neatest solution
var nIC = new Intl.Collator(undefined , {sensitivity: 'base'})
var cmp = nIC.compare.bind(nIC)
It will return 0 if the two strings are the same, ignoring accents.
Alternatively you try localecompare
'être'.localeCompare('etre',undefined,{sensitivity: 'base'})
回答7:
First, I'd recommend a switch statement instead of a long string of if-else if ...
Then, I am not sure why you don't like your current solution. It certainly is the cleanest one. What do you mean by not taking into account "all characters"?
There is no standard method in JavaScript to map accented letters to ASCII letters outside of using a third-party library, so the one you wrote is as good as any.
Also, "ß" I believe maps to "ss", not a single "s". And beware of "i" with and without dot in Turkish -- I believe they refer to different letters.
回答8:
You can also use http://fusejs.io, which describes itself as "Lightweight fuzzy-search library. Zero dependencies", for fuzzy searching.
来源：https://stackoverflow.com/questions/5700636/using-javascript-to-perform-text-matches-with-without-accented-characters