jquery find closest previous sibling with class

问题

here's the rough html I get to work with:

<li class="par_cat"></li>
<li class="sub_cat"></li>
<li class="sub_cat"></li>
<li class="par_cat"></li> // this is the single element I need to select
<li class="sub_cat"></li>
<li class="sub_cat"></li>
<li class="sub_cat current_sub"></li> // this is where I need to start searching
<li class="par_cat"></li>
<li class="sub_cat"></li>
<li class="par_cat"></li>

I need to traverse from the .current_sub, find the closest previous .par_cat and do stuff to it.

.find("li.par_cat") returns the whole load of .par_cat (I've got about 30 on the page). I need target the single one.

Would really appreciate any tips :)

回答1:

Try:

$('li.current_sub').prevAll("li.par_cat:first");

Tested it with your markup:

$('li.current_sub').prevAll("li.par_cat:first").text("woohoo");

will fill up the closest previous li.par_cat with "woohoo".

回答2:

Try

$('li.current_sub').prev('.par_cat').[do stuff];

回答3:

Using prevUntil() will allow us to get a distant sibling without having to get all. I had a particularly long set that was too CPU intensive using prevAll().

var category = $('li.current_sub').prev('li.par_cat');
if (category.length == 0){
  category = $('li.current_sub').prevUntil('li.par_cat').last().prev();
}
category.show();

This gets the first preceding sibling if it matches, otherwise it gets the sibling preceding the one that matches, so we just back up one more with prev() to get the desired element.

回答4:

I think all the answers are lacking something. I prefer using something like this

$('li.current_sub').prevUntil("li.par_cat").prev();

Saves you not adding :first inside the selector and is easier to read and understand. prevUntil() method has a better performance as well rather than using prevAll()

回答5:

You can follow this code:

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<script>
    $(document).ready(function () {
        $(".add").on("click", function () {
            var v = $(this).closest(".division").find("input[name='roll']").val();
            alert(v);
        });
    });
</script>
<?php

for ($i = 1; $i <= 5; $i++) {
    echo'<div class = "division">'
        . '<form method="POST" action="">'
        . '<p><input type="number" name="roll" placeholder="Enter Roll"></p>'
        . '<p><input type="button" class="add" name = "submit" value = "Click"></p>'
        . '</form></div>';
}
?>

You can get idea from this.

来源：https://stackoverflow.com/questions/2310270/jquery-find-closest-previous-sibling-with-class

标签

jquery

html

traversal

tree-traversal