Why can in-class initializers only use = or {}?

问题

In-class initializers (C++11 feature) must be enclosed in curly braces or follow a = sign. They may not be specified inside parenthesis.

What is the reason for this?

回答1:

I am not 100% positive about this, but this might be to prevent a syntax ambiguity. For example, consider the following class:

class BadTimes {
    struct Overloaded;
    int Overloaded;            // Legal, but a very strange idea.

    int confusing(Overloaded); // <-- This line
};

What does the indicated line mean? As written, this is a declaration of a member function named confusing that accepts as a parameter an object of type Overloaded (whose name isn't specified in the function declaration) and returns an int. If C++11 were to allow initializers to use parentheses, this would be ambiguous, because it could also be a definition of a member of type int named confusing that is initialized to the value of the data member Overloaded. (This is related to the current issue with the Most Vexing Parse.)

By requiring curly braces, this ambiguity is removed:

class BadTimes {
    struct Overloaded;
    int Overloaded;            // Legal, but a very strange idea.

    int confusing{Overloaded}; // <-- This line
};

Now, it's clear that confusing is actually an int initialized to the value of Overloaded, because there's no way to read it as a function declaration.

Hope this helps!

来源：https://stackoverflow.com/questions/16329962/why-can-in-class-initializers-only-use-or