jQuery Show-Hide DIV based on Checkbox Value

问题

Using AJAX I populate a DIV with a bunch of checkboxes (each with it's own unique ID). The IDs are "projectID1", "projectID2", "projectID3" and so on... I have given all checkboxes a class of "pChk".

My end goal is to show the DIV containing the Submit Button if ANY of the checkboxes are checked. The only time the DIV containing the Submit Button show be hidden is if all checkboxes are unchecked.

However the code I have come up with below shows/hides the Submit Button DIV for each checkbox instance. In other words, if I have three checkboxes CHECKED and I UNCHECK one of them, the Submit Button DIV get hidden.

Your expert advice is more than welcome!

function checkUncheck() { 
    $('.pChk').click(function() {
        if (this.checked) {
            $("#ProjectListButton").show();
        } else {
            $("#ProjectListButton").hide();
        }
    }); 
}

回答1:

While this is old if someone comes across this again (via search). The correct answer with jQuery 1.7 onwards is now:

$('.pChk').click(function() {
    if( $(this).is(':checked')) {
        $("#ProjectListButton").show();
    } else {
        $("#ProjectListButton").hide();
    }
});

回答2:

I use jQuery prop

$('#yourCheckbox').change(function(){
  if($(this).prop("checked")) {
    $('#showDiv').show();
  } else {
    $('#hideDiv').hide();
  }
});

回答3:

That is because you are only checking the current checkbox.

Change it to

function checkUncheck() { 
    $('.pChk').click(function() {
        if ( $('.pChk:checked').length > 0) {
            $("#ProjectListButton").show();
        } else {
            $("#ProjectListButton").hide();
        }
    }); 
}

to check if any of the checkboxes is checked (lots of checks in this line..).

reference: http://api.jquery.com/checked-selector/

回答4:

ebdiv is set style="display:none;"

it is works show & hide

$(document).ready(function(){
    $("#eb").click(function(){
        $("#ebdiv").toggle();
    });

});

回答5:

You might consider using the :checked selector, provided by jQuery. Something like this:

$('.pChk').click(function() {
    if( $('.pChk:checked').length > 0 ) {
        $("#ProjectListButton").show();
    } else {
        $("#ProjectListButton").hide();
    }
});

回答6:

A tip to all people that use flat-red, flat-green plugin, because of this plugin the answers above wont work!

In that case, use onchange="do_your_stuff();" on the label, for example: Your checkbox here

The reason why it doesn't work is that this Jquery creates a lot of objects around the real checkbox, so you can't see if it's changed or not.

But if someone click straight on checkbox, won't work :'(

回答7:

Try this

$('.yourchkboxes').change(function(){
    $('.yourbutton').toggle($('.yourchkboxes:checked').length > 0);
});

So it will check for at least one checkbox is checked or not.

来源：https://stackoverflow.com/questions/4444292/jquery-show-hide-div-based-on-checkbox-value

标签

jquery

checkbox

show-hide