问题
The following PHP code does exactly what I want to do. The problem is I need to re-create it in Perl and I've been playing around with the open()
and sysopen()
Perl functions but can't do it. Does anyone have any help or know of any links that might help? Thanks.
$URL = "http://example.com/api.php?arguments=values";
echo file_get_contents($URL);
回答1:
You can make use of LWP:
use LWP::Simple;
$contents = get $URL or die;
print $contents;
来源:https://stackoverflow.com/questions/3413151/perl-equivalent-of-phps-get-file-contents