问题
How would I select all table elements that do not have any descendant td elements using jQuery 1.3.2?
回答1:
You could try:
$("table:not(:has(tbody > tr > td))").doStuff();
Working example:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<script type="text/javascript">
$(function() {
$("table:not(:has(tbody > tr > td))").css("background", "yellow");
});
</script>
<style type="text/css">
table { border-collapse: collapse; }
td, th { border: 1px solid black; }
</style>
</head>
<body>
<table>
<tr>
<td>First table</td>
</tr>
</table>
<table>
<tr>
<th>Second table</th>
</tr>
</table>
</body>
</html>
回答2:
You're looking for the CSS :not() selector.
table *:not(td)
Should do it.
Edit: bah, misread what you wanted.
来源：https://stackoverflow.com/questions/1602098/jquery-selecting-elements-that-dont-have-a-specific-descendant-element