问题
I have a custom Keras layer and i use Theano as the backend and i want to do the following operation:
Suppose we have a tensor with shape (N,). I want to set the K first values to a fixed value x
(3 or whatever...). How do i do that? I assume i have to use argsort but i don't know how to implement it using Theano.
For example in a simple FF layer, how can i set the first N values of the tensor a
to a value x
?
def call(self, x, mask=None):
a = K.dot(x, self.W)
if self.bias:
a += self.b
return a
For example using numpy i can set the 10 first values of a
to 1 like this:
a[a.argsort() <= 10] = 1
I want to do the same using Keras backend functions or Theano functions.
回答1:
For a[a.argsort() <= 10] = 1
the equivalent code will be:
import numpy as np
from keras import backend as K
a = np.asarray([[3,4,2,44,22,4,5,6,77,86,3,2,3,23,44,21],
[3,4,22,44,2,4,54,6,77,8,3,2,36,23,4,2]], dtype=np.float)
a_t = K.variable(a)
a[a.argsort() <= 10] = 1
print a
arg_sort = K.T.argsort(a_t)
_cond = K.lesser_equal(arg_sort,10)
a_new = K.switch(_cond, 1, a_t)
print K.eval(a_new)
In a single statement it will be:
a_new = K.switch(K.lesser_equal(K.T.argsort(a_t),10), 1, a_t)
print K.eval(a_new)
I am not sure if this is exactly what you need.
来源:https://stackoverflow.com/questions/41915862/theano-keras-set-the-k-first-values-of-tensor-to-a-value