grep values and re-arranging the file

问题

hi i have a file name test.txt

    (standard input):8:      <property name="ProcedureName" value="abc"/>
(standard input):7:         <property name="PackageName" value="123abc"/>
(standard input):8:         <property name="ProcedureName" value="bac"/>
(standard input):7:      <property name="PackageName" value="bac123"/>
(standard input):8:      <property name="ProcedureName" value="cde"/>
(standard input):7:      <property name="PackageName" value="cd123"/>
(standard input):8:      <property name="ProcedureName" value="b4u"/>
(standard input):7:      <property name="PackageName" value="b4u234"/>

i have to grep only values of packagename and procdeurename from this file in the follwing format: into an o/p file

abc/123abc
bac/bac123
cde/cd123
b4u/b4u234

tried cut and awk but couldnt get that

回答1:

Try this awk:

awk -F'"' 'NR%2{p1=$4;next} {print p1 "/" $4}'

Test:

$ awk -F'"' 'NR%2{p1=$4;next} {print p1 "/" $4}' file
abc/123abc
bac/bac123
cde/cd123
b4u/b4u234

回答2:

With GNU grep and paste:

grep -oP '"\K[^"]*(?="/)' file | paste -d / - -

Output:

abc/123abc
bac/bac123
cde/cd123
b4u/b4u234

回答3:

My first attempt (and the one I'd actually recommend) was the same as @sat's so I deleted it and here's a different approach in case it's useful in some other context:

$ awk -F'"' '{n2v[$2]=$4} !(NR%2){print n2v["ProcedureName"] "/" n2v["PackageName"] }' file
abc/123abc
bac/bac123
cde/cd123
b4u/b4u234

n2v means name2value, an array name I often use for the type of application where we have name to value mappings in the input file.

回答4:

awk should be able to do this for you:

awk -F'"' 'BEGIN { OFS="/" } $2=="ProcedureName"{procedureName=$4} $2=="PackageName" { print procedureName,$4 }' yourfilename

This will use double-quote as the seperator. It tests for the string "ProcedureName" in position 2 and stores position 4 in the variable procedureName. Then if it finds "PackageName" in position 2, it prints out the stored procedureName and the stuff from position 4. And it uses backslash as the OutputFieldSeperator.

Technically you could pipe your grep to this, but awk can just do the search itself, which is what I've written up here.

回答5:

This might work for you (GNU sed):

sed 'N;s#.*value="\([^"]*\)".*value="\([^"]*\)".*#\1/\2#' file

Read two lines at a time and extract the values between double quotes preceeded by the literal value=.

Another slightly shorter version using a backreference in the LHS and -r option to make the regexp easier to read:

sed -r 'N;s#.*(value=")([^"]*)".*\1([^"]*)".*#\2/\3#' file

Yet another way, using the hold space and substitution:

sed -r 's/.*"(.*)".*/\1/;h;N;s//\1/;H;g;s#\n#/#' file

Extracts the last value between double quotes in two successive lines and re-arranges the results to the required string.

回答6:

As an alternative to awk and grep solutions.

sed -rn 's|.*"([^"]*)"/>|\1|p' xml | pr -2ats/

来源：https://stackoverflow.com/questions/32726286/grep-values-and-re-arranging-the-file

标签

shell

awk

sed

grep

cut