问题
Please help. How to make regex work in an if condition, to check user input(in 2nd parameter) must be not equal to any number?
set regex="^[0-9]+$"
if ($#argv == 2 && $2 != $regex) then
# do this
回答1:
grep-based solution that only works for non-negative integers.
#!/bin/csh
# Note this requires 2 command line arguments, and checks the second one
# cshell arguments are 0-indexed.
if ($#argv == 2) then
# Note the different grep regexp syntax, and you must use single quotes
set test = `echo $2 | grep '^[0-9]*$'`
if (($test) || ($test == 0)) then
echo "Bad input"
else
echo "Ok!"
endif
endif
来源:https://stackoverflow.com/questions/26457720/regex-to-check-if-input-is-number-in-cshunix